Metamath Proof Explorer


Theorem op2ndd

Description: Extract the second member of an ordered pair. (Contributed by Mario Carneiro, 31-Aug-2015)

Ref Expression
Hypotheses op1st.1
|- A e. _V
op1st.2
|- B e. _V
Assertion op2ndd
|- ( C = <. A , B >. -> ( 2nd ` C ) = B )

Proof

Step Hyp Ref Expression
1 op1st.1
 |-  A e. _V
2 op1st.2
 |-  B e. _V
3 fveq2
 |-  ( C = <. A , B >. -> ( 2nd ` C ) = ( 2nd ` <. A , B >. ) )
4 1 2 op2nd
 |-  ( 2nd ` <. A , B >. ) = B
5 3 4 eqtrdi
 |-  ( C = <. A , B >. -> ( 2nd ` C ) = B )