Metamath Proof Explorer


Theorem orim12da

Description: Deduce a disjunction from another one. Variation on orim12d . (Contributed by Thierry Arnoux, 18-May-2025)

Ref Expression
Hypotheses orim12da.1
|- ( ( ph /\ ps ) -> th )
orim12da.2
|- ( ( ph /\ ch ) -> ta )
orim12da.3
|- ( ph -> ( ps \/ ch ) )
Assertion orim12da
|- ( ph -> ( th \/ ta ) )

Proof

Step Hyp Ref Expression
1 orim12da.1
 |-  ( ( ph /\ ps ) -> th )
2 orim12da.2
 |-  ( ( ph /\ ch ) -> ta )
3 orim12da.3
 |-  ( ph -> ( ps \/ ch ) )
4 1 ex
 |-  ( ph -> ( ps -> th ) )
5 2 ex
 |-  ( ph -> ( ch -> ta ) )
6 4 5 orim12d
 |-  ( ph -> ( ( ps \/ ch ) -> ( th \/ ta ) ) )
7 3 6 mpd
 |-  ( ph -> ( th \/ ta ) )