Metamath Proof Explorer


Theorem oveq123d

Description: Equality deduction for operation value. (Contributed by FL, 22-Dec-2008)

Ref Expression
Hypotheses oveq123d.1
|- ( ph -> F = G )
oveq123d.2
|- ( ph -> A = B )
oveq123d.3
|- ( ph -> C = D )
Assertion oveq123d
|- ( ph -> ( A F C ) = ( B G D ) )

Proof

Step Hyp Ref Expression
1 oveq123d.1
 |-  ( ph -> F = G )
2 oveq123d.2
 |-  ( ph -> A = B )
3 oveq123d.3
 |-  ( ph -> C = D )
4 1 oveqd
 |-  ( ph -> ( A F C ) = ( A G C ) )
5 2 3 oveq12d
 |-  ( ph -> ( A G C ) = ( B G D ) )
6 4 5 eqtrd
 |-  ( ph -> ( A F C ) = ( B G D ) )