Metamath Proof Explorer


Theorem oveq1i

Description: Equality inference for operation value. (Contributed by NM, 28-Feb-1995)

Ref Expression
Hypothesis oveq1i.1
|- A = B
Assertion oveq1i
|- ( A F C ) = ( B F C )

Proof

Step Hyp Ref Expression
1 oveq1i.1
 |-  A = B
2 oveq1
 |-  ( A = B -> ( A F C ) = ( B F C ) )
3 1 2 ax-mp
 |-  ( A F C ) = ( B F C )