Metamath Proof Explorer


Theorem oveqan12rd

Description: Equality deduction for operation value. (Contributed by NM, 10-Aug-1995)

Ref Expression
Hypotheses oveq1d.1
|- ( ph -> A = B )
opreqan12i.2
|- ( ps -> C = D )
Assertion oveqan12rd
|- ( ( ps /\ ph ) -> ( A F C ) = ( B F D ) )

Proof

Step Hyp Ref Expression
1 oveq1d.1
 |-  ( ph -> A = B )
2 opreqan12i.2
 |-  ( ps -> C = D )
3 1 2 oveqan12d
 |-  ( ( ph /\ ps ) -> ( A F C ) = ( B F D ) )
4 3 ancoms
 |-  ( ( ps /\ ph ) -> ( A F C ) = ( B F D ) )