Metamath Proof Explorer


Theorem pm2.61iine

Description: Equality version of pm2.61ii . (Contributed by Scott Fenton, 13-Jun-2013) (Proof shortened by Wolf Lammen, 25-Nov-2019)

Ref Expression
Hypotheses pm2.61iine.1
|- ( ( A =/= C /\ B =/= D ) -> ph )
pm2.61iine.2
|- ( A = C -> ph )
pm2.61iine.3
|- ( B = D -> ph )
Assertion pm2.61iine
|- ph

Proof

Step Hyp Ref Expression
1 pm2.61iine.1
 |-  ( ( A =/= C /\ B =/= D ) -> ph )
2 pm2.61iine.2
 |-  ( A = C -> ph )
3 pm2.61iine.3
 |-  ( B = D -> ph )
4 3 adantl
 |-  ( ( A =/= C /\ B = D ) -> ph )
5 4 1 pm2.61dane
 |-  ( A =/= C -> ph )
6 2 5 pm2.61ine
 |-  ph