Metamath Proof Explorer


Theorem pw0

Description: Compute the power set of the empty set. Theorem 89 of Suppes p. 47. (Contributed by NM, 5-Aug-1993) (Proof shortened by Andrew Salmon, 29-Jun-2011)

Ref Expression
Assertion pw0
|- ~P (/) = { (/) }

Proof

Step Hyp Ref Expression
1 ss0b
 |-  ( x C_ (/) <-> x = (/) )
2 1 abbii
 |-  { x | x C_ (/) } = { x | x = (/) }
3 df-pw
 |-  ~P (/) = { x | x C_ (/) }
4 df-sn
 |-  { (/) } = { x | x = (/) }
5 2 3 4 3eqtr4i
 |-  ~P (/) = { (/) }