Metamath Proof Explorer


Theorem rabbiiaOLD

Description: Obsolete version of rabbiia as of 12-Jan-2025. (Contributed by NM, 22-May-1999) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypothesis rabbiia.1
|- ( x e. A -> ( ph <-> ps ) )
Assertion rabbiiaOLD
|- { x e. A | ph } = { x e. A | ps }

Proof

Step Hyp Ref Expression
1 rabbiia.1
 |-  ( x e. A -> ( ph <-> ps ) )
2 1 pm5.32i
 |-  ( ( x e. A /\ ph ) <-> ( x e. A /\ ps ) )
3 2 abbii
 |-  { x | ( x e. A /\ ph ) } = { x | ( x e. A /\ ps ) }
4 df-rab
 |-  { x e. A | ph } = { x | ( x e. A /\ ph ) }
5 df-rab
 |-  { x e. A | ps } = { x | ( x e. A /\ ps ) }
6 3 4 5 3eqtr4i
 |-  { x e. A | ph } = { x e. A | ps }