Metamath Proof Explorer


Theorem recjd

Description: Real part of a complex conjugate. (Contributed by Mario Carneiro, 29-May-2016)

Ref Expression
Hypothesis recld.1
|- ( ph -> A e. CC )
Assertion recjd
|- ( ph -> ( Re ` ( * ` A ) ) = ( Re ` A ) )

Proof

Step Hyp Ref Expression
1 recld.1
 |-  ( ph -> A e. CC )
2 recj
 |-  ( A e. CC -> ( Re ` ( * ` A ) ) = ( Re ` A ) )
3 1 2 syl
 |-  ( ph -> ( Re ` ( * ` A ) ) = ( Re ` A ) )