Metamath Proof Explorer


Theorem reglog1

Description: General log of 1 is 0. (Contributed by Stefan O'Rear, 19-Sep-2014) (New usage is discouraged.) Use logb1 instead.

Ref Expression
Assertion reglog1
|- ( ( C e. RR+ /\ C =/= 1 ) -> ( ( log ` 1 ) / ( log ` C ) ) = 0 )

Proof

Step Hyp Ref Expression
1 log1
 |-  ( log ` 1 ) = 0
2 1 oveq1i
 |-  ( ( log ` 1 ) / ( log ` C ) ) = ( 0 / ( log ` C ) )
3 relogcl
 |-  ( C e. RR+ -> ( log ` C ) e. RR )
4 3 recnd
 |-  ( C e. RR+ -> ( log ` C ) e. CC )
5 4 adantr
 |-  ( ( C e. RR+ /\ C =/= 1 ) -> ( log ` C ) e. CC )
6 logne0
 |-  ( ( C e. RR+ /\ C =/= 1 ) -> ( log ` C ) =/= 0 )
7 5 6 div0d
 |-  ( ( C e. RR+ /\ C =/= 1 ) -> ( 0 / ( log ` C ) ) = 0 )
8 2 7 eqtrid
 |-  ( ( C e. RR+ /\ C =/= 1 ) -> ( ( log ` 1 ) / ( log ` C ) ) = 0 )