Metamath Proof Explorer


Theorem rneqi

Description: Equality inference for range. (Contributed by NM, 4-Mar-2004)

Ref Expression
Hypothesis rneqi.1
|- A = B
Assertion rneqi
|- ran A = ran B

Proof

Step Hyp Ref Expression
1 rneqi.1
 |-  A = B
2 rneq
 |-  ( A = B -> ran A = ran B )
3 1 2 ax-mp
 |-  ran A = ran B