Metamath Proof Explorer


Theorem sb7f

Description: This version of dfsb7 does not require that ph and z be disjoint. This permits it to be used as a definition for substitution in a formalization that omits the logically redundant axiom ax-5 , i.e., that does not have the concept of a variable not occurring in a formula. (Definition dfsb1 is also suitable, but its mixing of free and bound variables is distasteful to some logicians.) Usage of this theorem is discouraged because it depends on ax-13 . (Contributed by NM, 26-Jul-2006) (Revised by Mario Carneiro, 6-Oct-2016) (New usage is discouraged.)

Ref Expression
Hypothesis sb7f.1
|- F/ z ph
Assertion sb7f
|- ( [ y / x ] ph <-> E. z ( z = y /\ E. x ( x = z /\ ph ) ) )

Proof

Step Hyp Ref Expression
1 sb7f.1
 |-  F/ z ph
2 1 sb5f
 |-  ( [ z / x ] ph <-> E. x ( x = z /\ ph ) )
3 2 sbbii
 |-  ( [ y / z ] [ z / x ] ph <-> [ y / z ] E. x ( x = z /\ ph ) )
4 1 sbco2
 |-  ( [ y / z ] [ z / x ] ph <-> [ y / x ] ph )
5 sb5
 |-  ( [ y / z ] E. x ( x = z /\ ph ) <-> E. z ( z = y /\ E. x ( x = z /\ ph ) ) )
6 3 4 5 3bitr3i
 |-  ( [ y / x ] ph <-> E. z ( z = y /\ E. x ( x = z /\ ph ) ) )