Metamath Proof Explorer


Theorem sbc6gOLD

Description: Obsolete version of sbc6g as of 5-Oct-2024. (Contributed by NM, 11-Oct-2004) (Proof shortened by Andrew Salmon, 8-Jun-2011) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion sbc6gOLD
|- ( A e. V -> ( [. A / x ]. ph <-> A. x ( x = A -> ph ) ) )

Proof

Step Hyp Ref Expression
1 sbc5
 |-  ( [. A / x ]. ph <-> E. x ( x = A /\ ph ) )
2 alexeqg
 |-  ( A e. V -> ( A. x ( x = A -> ph ) <-> E. x ( x = A /\ ph ) ) )
3 1 2 bitr4id
 |-  ( A e. V -> ( [. A / x ]. ph <-> A. x ( x = A -> ph ) ) )