Metamath Proof Explorer


Theorem sbcgOLD

Description: Obsolete version of sbcg as of 12-Oct-2024. (Contributed by Alan Sare, 10-Nov-2012) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion sbcgOLD
|- ( A e. V -> ( [. A / x ]. ph <-> ph ) )

Proof

Step Hyp Ref Expression
1 nfv
 |-  F/ x ph
2 1 sbcgf
 |-  ( A e. V -> ( [. A / x ]. ph <-> ph ) )