Metamath Proof Explorer


Theorem sbf

Description: Substitution for a variable not free in a wff does not affect it. For a version requiring disjoint variables but fewer axioms, see sbv . (Contributed by NM, 14-May-1993) (Revised by Mario Carneiro, 4-Oct-2016)

Ref Expression
Hypothesis sbf.1
|- F/ x ph
Assertion sbf
|- ( [ y / x ] ph <-> ph )

Proof

Step Hyp Ref Expression
1 sbf.1
 |-  F/ x ph
2 sbft
 |-  ( F/ x ph -> ( [ y / x ] ph <-> ph ) )
3 1 2 ax-mp
 |-  ( [ y / x ] ph <-> ph )