Metamath Proof Explorer


Theorem sbid2vw

Description: Reverting substitution yields the original expression. Based on fewer axioms than sbid2v , at the expense of an extra distinct variable condition. (Contributed by NM, 14-May-1993) (Revised by Wolf Lammen, 5-Aug-2023)

Ref Expression
Assertion sbid2vw
|- ( [ t / x ] [ x / t ] ph <-> ph )

Proof

Step Hyp Ref Expression
1 sbequ12r
 |-  ( x = t -> ( [ x / t ] ph <-> ph ) )
2 1 sbievw
 |-  ( [ t / x ] [ x / t ] ph <-> ph )