Metamath Proof Explorer


Theorem sbidm

Description: An idempotent law for substitution. Usage of this theorem is discouraged because it depends on ax-13 . (Contributed by NM, 30-Jun-1994) (Proof shortened by Andrew Salmon, 25-May-2011) (Proof shortened by Wolf Lammen, 13-Jul-2019) (New usage is discouraged.)

Ref Expression
Assertion sbidm
|- ( [ y / x ] [ y / x ] ph <-> [ y / x ] ph )

Proof

Step Hyp Ref Expression
1 sbcom3
 |-  ( [ y / x ] [ x / x ] ph <-> [ y / x ] [ y / x ] ph )
2 sbid
 |-  ( [ x / x ] ph <-> ph )
3 2 sbbii
 |-  ( [ y / x ] [ x / x ] ph <-> [ y / x ] ph )
4 1 3 bitr3i
 |-  ( [ y / x ] [ y / x ] ph <-> [ y / x ] ph )