Metamath Proof Explorer


Theorem sepab

Description: Separation Scheme (Aussonderung) in terms of a class abstraction. Prefer using the more natural statement rabexg . (Contributed by NM, 8-Jun-1994) Put in closed form. (Revised by BJ, 18-Jul-2026)

Ref Expression
Assertion sepab
|- ( A e. V -> { x | ( x e. A /\ ph ) } e. _V )

Proof

Step Hyp Ref Expression
1 id
 |-  ( A e. V -> A e. V )
2 ssab2
 |-  { x | ( x e. A /\ ph ) } C_ A
3 2 a1i
 |-  ( A e. V -> { x | ( x e. A /\ ph ) } C_ A )
4 1 3 ssexd
 |-  ( A e. V -> { x | ( x e. A /\ ph ) } e. _V )