Metamath Proof Explorer


Theorem simpri

Description: Inference eliminating a conjunct. (Contributed by NM, 15-Jun-1994)

Ref Expression
Hypothesis simpri.1
|- ( ph /\ ps )
Assertion simpri
|- ps

Proof

Step Hyp Ref Expression
1 simpri.1
 |-  ( ph /\ ps )
2 simpr
 |-  ( ( ph /\ ps ) -> ps )
3 1 2 ax-mp
 |-  ps