Theorem simprrd

Description: Deduction form of simprr , eliminating a double conjunct. (Contributed by Glauco Siliprandi, 11-Dec-2019)

	Ref	Expression
Hypothesis	simprrd.1	|- ( ph -> ( ps /\ ( ch /\ th ) ) )
Assertion	simprrd	|- ( ph -> th )

Proof

Step	Hyp	Ref	Expression
1		simprrd.1	|- ( ph -> ( ps /\ ( ch /\ th ) ) )
2	1	simprd	|- ( ph -> ( ch /\ th ) )
3	2	simprd	|- ( ph -> th )