Metamath Proof Explorer


Theorem speivw

Description: Version of spei with a disjoint variable condition, which does not require ax-13 (neither ax-7 nor ax-12 ). (Contributed by BJ, 31-May-2019)

Ref Expression
Hypotheses speivw.1
|- ( x = y -> ( ph <-> ps ) )
speivw.2
|- ps
Assertion speivw
|- E. x ph

Proof

Step Hyp Ref Expression
1 speivw.1
 |-  ( x = y -> ( ph <-> ps ) )
2 speivw.2
 |-  ps
3 1 biimprd
 |-  ( x = y -> ( ps -> ph ) )
4 3 2 speiv
 |-  E. x ph