Theorem spsd

Description: Deduction generalizing antecedent. (Contributed by NM, 17-Aug-1994)

	Ref	Expression
Hypothesis	spsd.1	|- ( ph -> ( ps -> ch ) )
Assertion	spsd	|- ( ph -> ( A. x ps -> ch ) )

Proof

Step	Hyp	Ref	Expression
1		spsd.1	|- ( ph -> ( ps -> ch ) )
2		sp	|- ( A. x ps -> ps )
3	2 1	syl5	|- ( ph -> ( A. x ps -> ch ) )