Description: The square function on complex numbers is continuous. (Contributed by NM, 13-Jun-2007) (Proof shortened by Mario Carneiro, 5-May-2014)
Ref | Expression | ||
---|---|---|---|
Hypothesis | sqcn.j | |- J = ( TopOpen ` CCfld ) |
|
Assertion | sqcn | |- ( x e. CC |-> ( x ^ 2 ) ) e. ( J Cn J ) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | sqcn.j | |- J = ( TopOpen ` CCfld ) |
|
2 | 2nn0 | |- 2 e. NN0 |
|
3 | 1 | expcn | |- ( 2 e. NN0 -> ( x e. CC |-> ( x ^ 2 ) ) e. ( J Cn J ) ) |
4 | 2 3 | ax-mp | |- ( x e. CC |-> ( x ^ 2 ) ) e. ( J Cn J ) |