Theorem sqvald

Description: Value of square. Inference version. (Contributed by Mario Carneiro, 28-May-2016)

	Ref	Expression
Hypothesis	expcld.1	|- ( ph -> A e. CC )
Assertion	sqvald	|- ( ph -> ( A ^ 2 ) = ( A x. A ) )

Proof

Step	Hyp	Ref	Expression
1		expcld.1	|- ( ph -> A e. CC )
2		sqval	|- ( A e. CC -> ( A ^ 2 ) = ( A x. A ) )
3	1 2	syl	|- ( ph -> ( A ^ 2 ) = ( A x. A ) )