Metamath Proof Explorer
Description: A chained subclass and equality deduction. (Contributed by NM, 25-Apr-2004)
|
|
Ref |
Expression |
|
Hypotheses |
sseqtrrdi.1 |
|- ( ph -> A C_ B ) |
|
|
sseqtrrdi.2 |
|- C = B |
|
Assertion |
sseqtrrdi |
|- ( ph -> A C_ C ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
sseqtrrdi.1 |
|- ( ph -> A C_ B ) |
| 2 |
|
sseqtrrdi.2 |
|- C = B |
| 3 |
2
|
eqcomi |
|- B = C |
| 4 |
1 3
|
sseqtrdi |
|- ( ph -> A C_ C ) |