Metamath Proof Explorer


Theorem ssex

Description: The subset of a set is also a set. Exercise 3 of TakeutiZaring p. 22. This is one way to express the Axiom of Separation ax-sep (a.k.a. Subset Axiom). (Contributed by NM, 27-Apr-1994)

Ref Expression
Hypothesis ssex.1
|- B e. _V
Assertion ssex
|- ( A C_ B -> A e. _V )

Proof

Step Hyp Ref Expression
1 ssex.1
 |-  B e. _V
2 df-ss
 |-  ( A C_ B <-> ( A i^i B ) = A )
3 1 inex2
 |-  ( A i^i B ) e. _V
4 eleq1
 |-  ( ( A i^i B ) = A -> ( ( A i^i B ) e. _V <-> A e. _V ) )
5 3 4 mpbii
 |-  ( ( A i^i B ) = A -> A e. _V )
6 2 5 sylbi
 |-  ( A C_ B -> A e. _V )