Metamath Proof Explorer


Theorem zfausclOLD

Description: Obsolete version of sepgi as of 14-Jul-2026. (Contributed by NM, 21-Jun-1993) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypothesis sepgi.1
|- A e. _V
Assertion zfausclOLD
|- E. y A. x ( x e. y <-> ( x e. A /\ ph ) )

Proof

Step Hyp Ref Expression
1 sepgi.1
 |-  A e. _V
2 eleq2
 |-  ( z = A -> ( x e. z <-> x e. A ) )
3 2 anbi1d
 |-  ( z = A -> ( ( x e. z /\ ph ) <-> ( x e. A /\ ph ) ) )
4 3 bibi2d
 |-  ( z = A -> ( ( x e. y <-> ( x e. z /\ ph ) ) <-> ( x e. y <-> ( x e. A /\ ph ) ) ) )
5 4 albidv
 |-  ( z = A -> ( A. x ( x e. y <-> ( x e. z /\ ph ) ) <-> A. x ( x e. y <-> ( x e. A /\ ph ) ) ) )
6 5 exbidv
 |-  ( z = A -> ( E. y A. x ( x e. y <-> ( x e. z /\ ph ) ) <-> E. y A. x ( x e. y <-> ( x e. A /\ ph ) ) ) )
7 ax-sep
 |-  E. y A. x ( x e. y <-> ( x e. z /\ ph ) )
8 1 6 7 vtocl
 |-  E. y A. x ( x e. y <-> ( x e. A /\ ph ) )