Metamath Proof Explorer


Theorem 0clwlk

Description: A pair of an empty set (of edges) and a second set (of vertices) is a closed walk if and only if the second set contains exactly one vertex (in an undirected graph). (Contributed by Alexander van der Vekens, 15-Mar-2018) (Revised by AV, 17-Feb-2021) (Revised by AV, 30-Oct-2021)

Ref Expression
Hypothesis 0clwlk.v V = Vtx G
Assertion 0clwlk G X ClWalks G P P : 0 0 V

Proof

Step Hyp Ref Expression
1 0clwlk.v V = Vtx G
2 1 0wlk G X Walks G P P : 0 0 V
3 2 anbi2d G X P 0 = P Walks G P P 0 = P P : 0 0 V
4 isclwlk ClWalks G P Walks G P P 0 = P
5 4 biancomi ClWalks G P P 0 = P Walks G P
6 hash0 = 0
7 6 eqcomi 0 =
8 7 fveq2i P 0 = P
9 8 biantrur P : 0 0 V P 0 = P P : 0 0 V
10 3 5 9 3bitr4g G X ClWalks G P P : 0 0 V