Metamath Proof Explorer


Theorem 0ram2

Description: The Ramsey number when M = 0 . (Contributed by Mario Carneiro, 22-Apr-2015)

Ref Expression
Assertion 0ram2 ⊢ R ∈ Fin ∧ R ≠ ∅ ∧ F : R ⟶ ℕ 0 → 0 Ramsey F = sup ran ⁡ F ℝ <

Proof

Step Hyp Ref Expression
1 frn ⊢ F : R ⟶ ℕ 0 → ran ⁡ F ⊆ ℕ 0
2 1 3ad2ant3 ⊢ R ∈ Fin ∧ R ≠ ∅ ∧ F : R ⟶ ℕ 0 → ran ⁡ F ⊆ ℕ 0
3 nn0ssz ⊢ ℕ 0 ⊆ ℤ
4 2 3 sstrdi ⊢ R ∈ Fin ∧ R ≠ ∅ ∧ F : R ⟶ ℕ 0 → ran ⁡ F ⊆ ℤ
5 nn0ssre ⊢ ℕ 0 ⊆ ℝ
6 2 5 sstrdi ⊢ R ∈ Fin ∧ R ≠ ∅ ∧ F : R ⟶ ℕ 0 → ran ⁡ F ⊆ ℝ
7 simp1 ⊢ R ∈ Fin ∧ R ≠ ∅ ∧ F : R ⟶ ℕ 0 → R ∈ Fin
8 ffn ⊢ F : R ⟶ ℕ 0 → F Fn R
9 8 3ad2ant3 ⊢ R ∈ Fin ∧ R ≠ ∅ ∧ F : R ⟶ ℕ 0 → F Fn R
10 dffn4 ⊢ F Fn R ↔ F : R ⟶ onto ran ⁡ F
11 9 10 sylib ⊢ R ∈ Fin ∧ R ≠ ∅ ∧ F : R ⟶ ℕ 0 → F : R ⟶ onto ran ⁡ F
12 fofi ⊢ R ∈ Fin ∧ F : R ⟶ onto ran ⁡ F → ran ⁡ F ∈ Fin
13 7 11 12 syl2anc ⊢ R ∈ Fin ∧ R ≠ ∅ ∧ F : R ⟶ ℕ 0 → ran ⁡ F ∈ Fin
14 fdm ⊢ F : R ⟶ ℕ 0 → dom ⁡ F = R
15 14 3ad2ant3 ⊢ R ∈ Fin ∧ R ≠ ∅ ∧ F : R ⟶ ℕ 0 → dom ⁡ F = R
16 simp2 ⊢ R ∈ Fin ∧ R ≠ ∅ ∧ F : R ⟶ ℕ 0 → R ≠ ∅
17 15 16 eqnetrd ⊢ R ∈ Fin ∧ R ≠ ∅ ∧ F : R ⟶ ℕ 0 → dom ⁡ F ≠ ∅
18 dm0rn0 ⊢ dom ⁡ F = ∅ ↔ ran ⁡ F = ∅
19 18 necon3bii ⊢ dom ⁡ F ≠ ∅ ↔ ran ⁡ F ≠ ∅
20 17 19 sylib ⊢ R ∈ Fin ∧ R ≠ ∅ ∧ F : R ⟶ ℕ 0 → ran ⁡ F ≠ ∅
21 fimaxre ⊢ ran ⁡ F ⊆ ℝ ∧ ran ⁡ F ∈ Fin ∧ ran ⁡ F ≠ ∅ → ∃ x ∈ ran ⁡ F ∀ y ∈ ran ⁡ F y ≤ x
22 6 13 20 21 syl3anc ⊢ R ∈ Fin ∧ R ≠ ∅ ∧ F : R ⟶ ℕ 0 → ∃ x ∈ ran ⁡ F ∀ y ∈ ran ⁡ F y ≤ x
23 ssrexv ⊢ ran ⁡ F ⊆ ℤ → ∃ x ∈ ran ⁡ F ∀ y ∈ ran ⁡ F y ≤ x → ∃ x ∈ ℤ ∀ y ∈ ran ⁡ F y ≤ x
24 4 22 23 sylc ⊢ R ∈ Fin ∧ R ≠ ∅ ∧ F : R ⟶ ℕ 0 → ∃ x ∈ ℤ ∀ y ∈ ran ⁡ F y ≤ x
25 0ram ⊢ R ∈ Fin ∧ R ≠ ∅ ∧ F : R ⟶ ℕ 0 ∧ ∃ x ∈ ℤ ∀ y ∈ ran ⁡ F y ≤ x → 0 Ramsey F = sup ran ⁡ F ℝ <
26 24 25 mpdan ⊢ R ∈ Fin ∧ R ≠ ∅ ∧ F : R ⟶ ℕ 0 → 0 Ramsey F = sup ran ⁡ F ℝ <