Metamath Proof Explorer


Theorem 1arithlem3

Description: Lemma for 1arith . (Contributed by Mario Carneiro, 30-May-2014)

Ref Expression
Hypothesis 1arith.1 M = n p p pCnt n
Assertion 1arithlem3 N M N : 0

Proof

Step Hyp Ref Expression
1 1arith.1 M = n p p pCnt n
2 1 1arithlem1 N M N = p p pCnt N
3 pccl p N p pCnt N 0
4 3 ancoms N p p pCnt N 0
5 2 4 fmpt3d N M N : 0