Metamath Proof Explorer


Theorem 1pthdlem2

Description: Lemma 2 for 1pthd . (Contributed by Alexander van der Vekens, 4-Dec-2017) (Revised by AV, 22-Jan-2021)

Ref Expression
Hypotheses 1wlkd.p ⊢ P = ⟨“ XY ”⟩
1wlkd.f ⊢ F = ⟨“ J ”⟩
Assertion 1pthdlem2 ⊢ P 0 F ∩ P 1 ..^ F = ∅

Proof

Step Hyp Ref Expression
1 1wlkd.p ⊢ P = ⟨“ XY ”⟩
2 1wlkd.f ⊢ F = ⟨“ J ”⟩
3 2 fveq2i ⊢ F = ⟨“ J ”⟩
4 s1len ⊢ ⟨“ J ”⟩ = 1
5 3 4 eqtri ⊢ F = 1
6 5 oveq2i ⊢ 1 ..^ F = 1 ..^ 1
7 fzo0 ⊢ 1 ..^ 1 = ∅
8 6 7 eqtri ⊢ 1 ..^ F = ∅
9 8 imaeq2i ⊢ P 1 ..^ F = P ∅
10 9 ineq2i ⊢ P 0 F ∩ P 1 ..^ F = P 0 F ∩ P ∅
11 ima0 ⊢ P ∅ = ∅
12 11 ineq2i ⊢ P 0 F ∩ P ∅ = P 0 F ∩ ∅
13 in0 ⊢ P 0 F ∩ ∅ = ∅
14 12 13 eqtri ⊢ P 0 F ∩ P ∅ = ∅
15 10 14 eqtri ⊢ P 0 F ∩ P 1 ..^ F = ∅