Metamath Proof Explorer


Theorem 1stpreima

Description: The preimage by 1st is a 'vertical band'. (Contributed by Thierry Arnoux, 13-Oct-2017)

Ref Expression
Assertion 1stpreima ⊢ A ⊆ B → 1 st ↾ B × C -1 A = A × C

Proof

Step Hyp Ref Expression
1 elxp7 ⊢ w ∈ B × C ↔ w ∈ V × V ∧ 1 st ⁡ w ∈ B ∧ 2 nd ⁡ w ∈ C
2 1 anbi2i ⊢ 1 st ⁡ w ∈ A ∧ w ∈ B × C ↔ 1 st ⁡ w ∈ A ∧ w ∈ V × V ∧ 1 st ⁡ w ∈ B ∧ 2 nd ⁡ w ∈ C
3 anass ⊢ 1 st ⁡ w ∈ A ∧ 1 st ⁡ w ∈ B ∧ w ∈ V × V ∧ 2 nd ⁡ w ∈ C ↔ 1 st ⁡ w ∈ A ∧ 1 st ⁡ w ∈ B ∧ w ∈ V × V ∧ 2 nd ⁡ w ∈ C
4 3 a1i ⊢ A ⊆ B → 1 st ⁡ w ∈ A ∧ 1 st ⁡ w ∈ B ∧ w ∈ V × V ∧ 2 nd ⁡ w ∈ C ↔ 1 st ⁡ w ∈ A ∧ 1 st ⁡ w ∈ B ∧ w ∈ V × V ∧ 2 nd ⁡ w ∈ C
5 ssel ⊢ A ⊆ B → 1 st ⁡ w ∈ A → 1 st ⁡ w ∈ B
6 5 pm4.71d ⊢ A ⊆ B → 1 st ⁡ w ∈ A ↔ 1 st ⁡ w ∈ A ∧ 1 st ⁡ w ∈ B
7 6 anbi1d ⊢ A ⊆ B → 1 st ⁡ w ∈ A ∧ w ∈ V × V ∧ 2 nd ⁡ w ∈ C ↔ 1 st ⁡ w ∈ A ∧ 1 st ⁡ w ∈ B ∧ w ∈ V × V ∧ 2 nd ⁡ w ∈ C
8 an12 ⊢ w ∈ V × V ∧ 1 st ⁡ w ∈ B ∧ 2 nd ⁡ w ∈ C ↔ 1 st ⁡ w ∈ B ∧ w ∈ V × V ∧ 2 nd ⁡ w ∈ C
9 8 anbi2i ⊢ 1 st ⁡ w ∈ A ∧ w ∈ V × V ∧ 1 st ⁡ w ∈ B ∧ 2 nd ⁡ w ∈ C ↔ 1 st ⁡ w ∈ A ∧ 1 st ⁡ w ∈ B ∧ w ∈ V × V ∧ 2 nd ⁡ w ∈ C
10 9 a1i ⊢ A ⊆ B → 1 st ⁡ w ∈ A ∧ w ∈ V × V ∧ 1 st ⁡ w ∈ B ∧ 2 nd ⁡ w ∈ C ↔ 1 st ⁡ w ∈ A ∧ 1 st ⁡ w ∈ B ∧ w ∈ V × V ∧ 2 nd ⁡ w ∈ C
11 4 7 10 3bitr4d ⊢ A ⊆ B → 1 st ⁡ w ∈ A ∧ w ∈ V × V ∧ 2 nd ⁡ w ∈ C ↔ 1 st ⁡ w ∈ A ∧ w ∈ V × V ∧ 1 st ⁡ w ∈ B ∧ 2 nd ⁡ w ∈ C
12 2 11 bitr4id ⊢ A ⊆ B → 1 st ⁡ w ∈ A ∧ w ∈ B × C ↔ 1 st ⁡ w ∈ A ∧ w ∈ V × V ∧ 2 nd ⁡ w ∈ C
13 an12 ⊢ 1 st ⁡ w ∈ A ∧ w ∈ V × V ∧ 2 nd ⁡ w ∈ C ↔ w ∈ V × V ∧ 1 st ⁡ w ∈ A ∧ 2 nd ⁡ w ∈ C
14 12 13 bitrdi ⊢ A ⊆ B → 1 st ⁡ w ∈ A ∧ w ∈ B × C ↔ w ∈ V × V ∧ 1 st ⁡ w ∈ A ∧ 2 nd ⁡ w ∈ C
15 cnvresima ⊢ 1 st ↾ B × C -1 A = 1 st -1 A ∩ B × C
16 15 eleq2i ⊢ w ∈ 1 st ↾ B × C -1 A ↔ w ∈ 1 st -1 A ∩ B × C
17 elin ⊢ w ∈ 1 st -1 A ∩ B × C ↔ w ∈ 1 st -1 A ∧ w ∈ B × C
18 vex ⊢ w ∈ V
19 fo1st ⊢ 1 st : V ⟶ onto V
20 fofn ⊢ 1 st : V ⟶ onto V → 1 st Fn V
21 elpreima ⊢ 1 st Fn V → w ∈ 1 st -1 A ↔ w ∈ V ∧ 1 st ⁡ w ∈ A
22 19 20 21 mp2b ⊢ w ∈ 1 st -1 A ↔ w ∈ V ∧ 1 st ⁡ w ∈ A
23 18 22 mpbiran ⊢ w ∈ 1 st -1 A ↔ 1 st ⁡ w ∈ A
24 23 anbi1i ⊢ w ∈ 1 st -1 A ∧ w ∈ B × C ↔ 1 st ⁡ w ∈ A ∧ w ∈ B × C
25 16 17 24 3bitri ⊢ w ∈ 1 st ↾ B × C -1 A ↔ 1 st ⁡ w ∈ A ∧ w ∈ B × C
26 elxp7 ⊢ w ∈ A × C ↔ w ∈ V × V ∧ 1 st ⁡ w ∈ A ∧ 2 nd ⁡ w ∈ C
27 14 25 26 3bitr4g ⊢ A ⊆ B → w ∈ 1 st ↾ B × C -1 A ↔ w ∈ A × C
28 27 eqrdv ⊢ A ⊆ B → 1 st ↾ B × C -1 A = A × C