Metamath Proof Explorer


Theorem 1stpreimas

Description: The preimage of a singleton. (Contributed by Thierry Arnoux, 27-Apr-2020)

Ref Expression
Assertion 1stpreimas ⊢ Rel ⁡ A ∧ X ∈ V → 1 st ↾ A -1 X = X × A X

Proof

Step Hyp Ref Expression
1 1st2ndb ⊢ z ∈ V × V ↔ z = 1 st ⁡ z 2 nd ⁡ z
2 1 biimpi ⊢ z ∈ V × V → z = 1 st ⁡ z 2 nd ⁡ z
3 2 ad2antrl ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ V × V ∧ 1 st ⁡ z ∈ X ∧ 2 nd ⁡ z ∈ A X → z = 1 st ⁡ z 2 nd ⁡ z
4 fvex ⊢ 1 st ⁡ z ∈ V
5 4 elsn ⊢ 1 st ⁡ z ∈ X ↔ 1 st ⁡ z = X
6 5 biimpi ⊢ 1 st ⁡ z ∈ X → 1 st ⁡ z = X
7 6 ad2antrl ⊢ z ∈ V × V ∧ 1 st ⁡ z ∈ X ∧ 2 nd ⁡ z ∈ A X → 1 st ⁡ z = X
8 7 adantl ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ V × V ∧ 1 st ⁡ z ∈ X ∧ 2 nd ⁡ z ∈ A X → 1 st ⁡ z = X
9 8 opeq1d ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ V × V ∧ 1 st ⁡ z ∈ X ∧ 2 nd ⁡ z ∈ A X → 1 st ⁡ z 2 nd ⁡ z = X 2 nd ⁡ z
10 3 9 eqtrd ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ V × V ∧ 1 st ⁡ z ∈ X ∧ 2 nd ⁡ z ∈ A X → z = X 2 nd ⁡ z
11 simplr ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ V × V ∧ 1 st ⁡ z ∈ X ∧ 2 nd ⁡ z ∈ A X → X ∈ V
12 simprrr ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ V × V ∧ 1 st ⁡ z ∈ X ∧ 2 nd ⁡ z ∈ A X → 2 nd ⁡ z ∈ A X
13 elimasng ⊢ X ∈ V ∧ 2 nd ⁡ z ∈ A X → 2 nd ⁡ z ∈ A X ↔ X 2 nd ⁡ z ∈ A
14 13 biimpa ⊢ X ∈ V ∧ 2 nd ⁡ z ∈ A X ∧ 2 nd ⁡ z ∈ A X → X 2 nd ⁡ z ∈ A
15 11 12 12 14 syl21anc ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ V × V ∧ 1 st ⁡ z ∈ X ∧ 2 nd ⁡ z ∈ A X → X 2 nd ⁡ z ∈ A
16 10 15 eqeltrd ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ V × V ∧ 1 st ⁡ z ∈ X ∧ 2 nd ⁡ z ∈ A X → z ∈ A
17 fvres ⊢ z ∈ A → 1 st ↾ A ⁡ z = 1 st ⁡ z
18 16 17 syl ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ V × V ∧ 1 st ⁡ z ∈ X ∧ 2 nd ⁡ z ∈ A X → 1 st ↾ A ⁡ z = 1 st ⁡ z
19 18 8 eqtrd ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ V × V ∧ 1 st ⁡ z ∈ X ∧ 2 nd ⁡ z ∈ A X → 1 st ↾ A ⁡ z = X
20 16 19 jca ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ V × V ∧ 1 st ⁡ z ∈ X ∧ 2 nd ⁡ z ∈ A X → z ∈ A ∧ 1 st ↾ A ⁡ z = X
21 df-rel ⊢ Rel ⁡ A ↔ A ⊆ V × V
22 21 birani ⊢ Rel ⁡ A ∧ X ∈ V → A ⊆ V × V
23 22 sselda ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ A → z ∈ V × V
24 23 adantrr ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ A ∧ 1 st ↾ A ⁡ z = X → z ∈ V × V
25 17 ad2antrl ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ A ∧ 1 st ↾ A ⁡ z = X → 1 st ↾ A ⁡ z = 1 st ⁡ z
26 simprr ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ A ∧ 1 st ↾ A ⁡ z = X → 1 st ↾ A ⁡ z = X
27 25 26 eqtr3d ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ A ∧ 1 st ↾ A ⁡ z = X → 1 st ⁡ z = X
28 27 5 sylibr ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ A ∧ 1 st ↾ A ⁡ z = X → 1 st ⁡ z ∈ X
29 27 28 eqeltrrd ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ A ∧ 1 st ↾ A ⁡ z = X → X ∈ X
30 simpr ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ A ∧ 1 st ↾ A ⁡ z = X ∧ x = X → x = X
31 30 opeq1d ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ A ∧ 1 st ↾ A ⁡ z = X ∧ x = X → x 2 nd ⁡ z = X 2 nd ⁡ z
32 31 eleq1d ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ A ∧ 1 st ↾ A ⁡ z = X ∧ x = X → x 2 nd ⁡ z ∈ A ↔ X 2 nd ⁡ z ∈ A
33 1st2nd ⊢ Rel ⁡ A ∧ z ∈ A → z = 1 st ⁡ z 2 nd ⁡ z
34 33 ad2ant2r ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ A ∧ 1 st ↾ A ⁡ z = X → z = 1 st ⁡ z 2 nd ⁡ z
35 27 opeq1d ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ A ∧ 1 st ↾ A ⁡ z = X → 1 st ⁡ z 2 nd ⁡ z = X 2 nd ⁡ z
36 34 35 eqtrd ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ A ∧ 1 st ↾ A ⁡ z = X → z = X 2 nd ⁡ z
37 simprl ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ A ∧ 1 st ↾ A ⁡ z = X → z ∈ A
38 36 37 eqeltrrd ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ A ∧ 1 st ↾ A ⁡ z = X → X 2 nd ⁡ z ∈ A
39 29 32 38 rspcedvd ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ A ∧ 1 st ↾ A ⁡ z = X → ∃ x ∈ X x 2 nd ⁡ z ∈ A
40 df-rex ⊢ ∃ x ∈ X x 2 nd ⁡ z ∈ A ↔ ∃ x x ∈ X ∧ x 2 nd ⁡ z ∈ A
41 39 40 sylib ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ A ∧ 1 st ↾ A ⁡ z = X → ∃ x x ∈ X ∧ x 2 nd ⁡ z ∈ A
42 fvex ⊢ 2 nd ⁡ z ∈ V
43 42 elima3 ⊢ 2 nd ⁡ z ∈ A X ↔ ∃ x x ∈ X ∧ x 2 nd ⁡ z ∈ A
44 41 43 sylibr ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ A ∧ 1 st ↾ A ⁡ z = X → 2 nd ⁡ z ∈ A X
45 28 44 jca ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ A ∧ 1 st ↾ A ⁡ z = X → 1 st ⁡ z ∈ X ∧ 2 nd ⁡ z ∈ A X
46 24 45 jca ⊢ Rel ⁡ A ∧ X ∈ V ∧ z ∈ A ∧ 1 st ↾ A ⁡ z = X → z ∈ V × V ∧ 1 st ⁡ z ∈ X ∧ 2 nd ⁡ z ∈ A X
47 20 46 impbida ⊢ Rel ⁡ A ∧ X ∈ V → z ∈ V × V ∧ 1 st ⁡ z ∈ X ∧ 2 nd ⁡ z ∈ A X ↔ z ∈ A ∧ 1 st ↾ A ⁡ z = X
48 elxp7 ⊢ z ∈ X × A X ↔ z ∈ V × V ∧ 1 st ⁡ z ∈ X ∧ 2 nd ⁡ z ∈ A X
49 48 a1i ⊢ Rel ⁡ A ∧ X ∈ V → z ∈ X × A X ↔ z ∈ V × V ∧ 1 st ⁡ z ∈ X ∧ 2 nd ⁡ z ∈ A X
50 fo1st ⊢ 1 st : V ⟶ onto V
51 fofn ⊢ 1 st : V ⟶ onto V → 1 st Fn V
52 50 51 ax-mp ⊢ 1 st Fn V
53 ssv ⊢ A ⊆ V
54 fnssres ⊢ 1 st Fn V ∧ A ⊆ V → 1 st ↾ A Fn A
55 52 53 54 mp2an ⊢ 1 st ↾ A Fn A
56 fniniseg ⊢ 1 st ↾ A Fn A → z ∈ 1 st ↾ A -1 X ↔ z ∈ A ∧ 1 st ↾ A ⁡ z = X
57 55 56 ax-mp ⊢ z ∈ 1 st ↾ A -1 X ↔ z ∈ A ∧ 1 st ↾ A ⁡ z = X
58 57 a1i ⊢ Rel ⁡ A ∧ X ∈ V → z ∈ 1 st ↾ A -1 X ↔ z ∈ A ∧ 1 st ↾ A ⁡ z = X
59 47 49 58 3bitr4rd ⊢ Rel ⁡ A ∧ X ∈ V → z ∈ 1 st ↾ A -1 X ↔ z ∈ X × A X
60 59 eqrdv ⊢ Rel ⁡ A ∧ X ∈ V → 1 st ↾ A -1 X = X × A X