Metamath Proof Explorer


Theorem 1wlkdlem2

Description: Lemma 2 for 1wlkd . (Contributed by AV, 22-Jan-2021)

Ref Expression
Hypotheses 1wlkd.p ⊢ P = ⟨“ XY ”⟩
1wlkd.f ⊢ F = ⟨“ J ”⟩
1wlkd.x ⊢ φ → X ∈ V
1wlkd.y ⊢ φ → Y ∈ V
1wlkd.l ⊢ φ ∧ X = Y → I ⁡ J = X
1wlkd.j ⊢ φ ∧ X ≠ Y → X Y ⊆ I ⁡ J
Assertion 1wlkdlem2 ⊢ φ → X ∈ I ⁡ J

Proof

Step Hyp Ref Expression
1 1wlkd.p ⊢ P = ⟨“ XY ”⟩
2 1wlkd.f ⊢ F = ⟨“ J ”⟩
3 1wlkd.x ⊢ φ → X ∈ V
4 1wlkd.y ⊢ φ → Y ∈ V
5 1wlkd.l ⊢ φ ∧ X = Y → I ⁡ J = X
6 1wlkd.j ⊢ φ ∧ X ≠ Y → X Y ⊆ I ⁡ J
7 snidg ⊢ X ∈ V → X ∈ X
8 3 7 syl ⊢ φ → X ∈ X
9 8 adantr ⊢ φ ∧ X = Y → X ∈ X
10 9 5 eleqtrrd ⊢ φ ∧ X = Y → X ∈ I ⁡ J
11 4 adantr ⊢ φ ∧ X ≠ Y → Y ∈ V
12 prssg ⊢ X ∈ V ∧ Y ∈ V → X ∈ I ⁡ J ∧ Y ∈ I ⁡ J ↔ X Y ⊆ I ⁡ J
13 3 11 12 syl2an2r ⊢ φ ∧ X ≠ Y → X ∈ I ⁡ J ∧ Y ∈ I ⁡ J ↔ X Y ⊆ I ⁡ J
14 6 13 mpbird ⊢ φ ∧ X ≠ Y → X ∈ I ⁡ J ∧ Y ∈ I ⁡ J
15 14 simpld ⊢ φ ∧ X ≠ Y → X ∈ I ⁡ J
16 10 15 pm2.61dane ⊢ φ → X ∈ I ⁡ J