Metamath Proof Explorer


Theorem 2exp7

Description: Two to the seventh power is 128. (Contributed by AV, 16-Aug-2021)

Ref Expression
Assertion 2exp7 ⊢ 2 7 = 128

Proof

Step Hyp Ref Expression
1 df-7 ⊢ 7 = 6 + 1
2 1 oveq2i ⊢ 2 7 = 2 6 + 1
3 2cn ⊢ 2 ∈ ℂ
4 6nn0 ⊢ 6 ∈ ℕ 0
5 expp1 ⊢ 2 ∈ ℂ ∧ 6 ∈ ℕ 0 → 2 6 + 1 = 2 6 ⋅ 2
6 3 4 5 mp2an ⊢ 2 6 + 1 = 2 6 ⋅ 2
7 2exp6 ⊢ 2 6 = 64
8 7 oveq1i ⊢ 2 6 ⋅ 2 = 64 ⋅ 2
9 6 8 eqtri ⊢ 2 6 + 1 = 64 ⋅ 2
10 2 9 eqtri ⊢ 2 7 = 64 ⋅ 2
11 2nn0 ⊢ 2 ∈ ℕ 0
12 4nn0 ⊢ 4 ∈ ℕ 0
13 eqid ⊢ 64 = 64
14 6t2e12 ⊢ 6 ⋅ 2 = 12
15 4t2e8 ⊢ 4 ⋅ 2 = 8
16 11 4 12 13 14 15 decmul1 ⊢ 64 ⋅ 2 = 128
17 10 16 eqtri ⊢ 2 7 = 128