Metamath Proof Explorer


Theorem 2lgslem3c

Description: Lemma for 2lgslem3c1 . (Contributed by AV, 16-Jul-2021)

Ref Expression
Hypothesis 2lgslem2.n ⊢ N = P − 1 2 − P 4
Assertion 2lgslem3c ⊢ K ∈ ℕ 0 ∧ P = 8 ⁢ K + 5 → N = 2 ⁢ K + 1

Proof

Step Hyp Ref Expression
1 2lgslem2.n ⊢ N = P − 1 2 − P 4
2 oveq1 ⊢ P = 8 ⁢ K + 5 → P − 1 = 8 ⁢ K + 5 - 1
3 2 oveq1d ⊢ P = 8 ⁢ K + 5 → P − 1 2 = 8 ⁢ K + 5 - 1 2
4 fvoveq1 ⊢ P = 8 ⁢ K + 5 → P 4 = 8 ⁢ K + 5 4
5 3 4 oveq12d ⊢ P = 8 ⁢ K + 5 → P − 1 2 − P 4 = 8 ⁢ K + 5 - 1 2 − 8 ⁢ K + 5 4
6 1 5 eqtrid ⊢ P = 8 ⁢ K + 5 → N = 8 ⁢ K + 5 - 1 2 − 8 ⁢ K + 5 4
7 8nn0 ⊢ 8 ∈ ℕ 0
8 7 a1i ⊢ K ∈ ℕ 0 → 8 ∈ ℕ 0
9 id ⊢ K ∈ ℕ 0 → K ∈ ℕ 0
10 8 9 nn0mulcld ⊢ K ∈ ℕ 0 → 8 ⁢ K ∈ ℕ 0
11 10 nn0cnd ⊢ K ∈ ℕ 0 → 8 ⁢ K ∈ ℂ
12 5cn ⊢ 5 ∈ ℂ
13 12 a1i ⊢ K ∈ ℕ 0 → 5 ∈ ℂ
14 1cnd ⊢ K ∈ ℕ 0 → 1 ∈ ℂ
15 11 13 14 addsubassd ⊢ K ∈ ℕ 0 → 8 ⁢ K + 5 - 1 = 8 ⁢ K + 5 - 1
16 4t2e8 ⊢ 4 ⋅ 2 = 8
17 16 eqcomi ⊢ 8 = 4 ⋅ 2
18 17 a1i ⊢ K ∈ ℕ 0 → 8 = 4 ⋅ 2
19 18 oveq1d ⊢ K ∈ ℕ 0 → 8 ⁢ K = 4 ⋅ 2 ⁢ K
20 4cn ⊢ 4 ∈ ℂ
21 20 a1i ⊢ K ∈ ℕ 0 → 4 ∈ ℂ
22 2cn ⊢ 2 ∈ ℂ
23 22 a1i ⊢ K ∈ ℕ 0 → 2 ∈ ℂ
24 nn0cn ⊢ K ∈ ℕ 0 → K ∈ ℂ
25 21 23 24 mul32d ⊢ K ∈ ℕ 0 → 4 ⋅ 2 ⁢ K = 4 ⁢ K ⋅ 2
26 19 25 eqtrd ⊢ K ∈ ℕ 0 → 8 ⁢ K = 4 ⁢ K ⋅ 2
27 5m1e4 ⊢ 5 − 1 = 4
28 27 a1i ⊢ K ∈ ℕ 0 → 5 − 1 = 4
29 26 28 oveq12d ⊢ K ∈ ℕ 0 → 8 ⁢ K + 5 - 1 = 4 ⁢ K ⋅ 2 + 4
30 15 29 eqtrd ⊢ K ∈ ℕ 0 → 8 ⁢ K + 5 - 1 = 4 ⁢ K ⋅ 2 + 4
31 30 oveq1d ⊢ K ∈ ℕ 0 → 8 ⁢ K + 5 - 1 2 = 4 ⁢ K ⋅ 2 + 4 2
32 4nn0 ⊢ 4 ∈ ℕ 0
33 32 a1i ⊢ K ∈ ℕ 0 → 4 ∈ ℕ 0
34 33 9 nn0mulcld ⊢ K ∈ ℕ 0 → 4 ⁢ K ∈ ℕ 0
35 34 nn0cnd ⊢ K ∈ ℕ 0 → 4 ⁢ K ∈ ℂ
36 35 23 mulcld ⊢ K ∈ ℕ 0 → 4 ⁢ K ⋅ 2 ∈ ℂ
37 2rp ⊢ 2 ∈ ℝ +
38 37 a1i ⊢ K ∈ ℕ 0 → 2 ∈ ℝ +
39 38 rpcnne0d ⊢ K ∈ ℕ 0 → 2 ∈ ℂ ∧ 2 ≠ 0
40 divdir ⊢ 4 ⁢ K ⋅ 2 ∈ ℂ ∧ 4 ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 → 4 ⁢ K ⋅ 2 + 4 2 = 4 ⁢ K ⋅ 2 2 + 4 2
41 36 21 39 40 syl3anc ⊢ K ∈ ℕ 0 → 4 ⁢ K ⋅ 2 + 4 2 = 4 ⁢ K ⋅ 2 2 + 4 2
42 2ne0 ⊢ 2 ≠ 0
43 42 a1i ⊢ K ∈ ℕ 0 → 2 ≠ 0
44 35 23 43 divcan4d ⊢ K ∈ ℕ 0 → 4 ⁢ K ⋅ 2 2 = 4 ⁢ K
45 4div2e2 ⊢ 4 2 = 2
46 45 a1i ⊢ K ∈ ℕ 0 → 4 2 = 2
47 44 46 oveq12d ⊢ K ∈ ℕ 0 → 4 ⁢ K ⋅ 2 2 + 4 2 = 4 ⁢ K + 2
48 31 41 47 3eqtrd ⊢ K ∈ ℕ 0 → 8 ⁢ K + 5 - 1 2 = 4 ⁢ K + 2
49 4ne0 ⊢ 4 ≠ 0
50 20 49 pm3.2i ⊢ 4 ∈ ℂ ∧ 4 ≠ 0
51 50 a1i ⊢ K ∈ ℕ 0 → 4 ∈ ℂ ∧ 4 ≠ 0
52 divdir ⊢ 8 ⁢ K ∈ ℂ ∧ 5 ∈ ℂ ∧ 4 ∈ ℂ ∧ 4 ≠ 0 → 8 ⁢ K + 5 4 = 8 ⁢ K 4 + 5 4
53 11 13 51 52 syl3anc ⊢ K ∈ ℕ 0 → 8 ⁢ K + 5 4 = 8 ⁢ K 4 + 5 4
54 8cn ⊢ 8 ∈ ℂ
55 54 a1i ⊢ K ∈ ℕ 0 → 8 ∈ ℂ
56 div23 ⊢ 8 ∈ ℂ ∧ K ∈ ℂ ∧ 4 ∈ ℂ ∧ 4 ≠ 0 → 8 ⁢ K 4 = 8 4 ⁢ K
57 55 24 51 56 syl3anc ⊢ K ∈ ℕ 0 → 8 ⁢ K 4 = 8 4 ⁢ K
58 17 oveq1i ⊢ 8 4 = 4 ⋅ 2 4
59 22 20 49 divcan3i ⊢ 4 ⋅ 2 4 = 2
60 58 59 eqtri ⊢ 8 4 = 2
61 60 a1i ⊢ K ∈ ℕ 0 → 8 4 = 2
62 61 oveq1d ⊢ K ∈ ℕ 0 → 8 4 ⁢ K = 2 ⁢ K
63 57 62 eqtrd ⊢ K ∈ ℕ 0 → 8 ⁢ K 4 = 2 ⁢ K
64 63 oveq1d ⊢ K ∈ ℕ 0 → 8 ⁢ K 4 + 5 4 = 2 ⁢ K + 5 4
65 53 64 eqtrd ⊢ K ∈ ℕ 0 → 8 ⁢ K + 5 4 = 2 ⁢ K + 5 4
66 65 fveq2d ⊢ K ∈ ℕ 0 → 8 ⁢ K + 5 4 = 2 ⁢ K + 5 4
67 1lt4 ⊢ 1 < 4
68 2nn0 ⊢ 2 ∈ ℕ 0
69 68 a1i ⊢ K ∈ ℕ 0 → 2 ∈ ℕ 0
70 69 9 nn0mulcld ⊢ K ∈ ℕ 0 → 2 ⁢ K ∈ ℕ 0
71 70 nn0zd ⊢ K ∈ ℕ 0 → 2 ⁢ K ∈ ℤ
72 71 peano2zd ⊢ K ∈ ℕ 0 → 2 ⁢ K + 1 ∈ ℤ
73 1nn0 ⊢ 1 ∈ ℕ 0
74 73 a1i ⊢ K ∈ ℕ 0 → 1 ∈ ℕ 0
75 4nn ⊢ 4 ∈ ℕ
76 75 a1i ⊢ K ∈ ℕ 0 → 4 ∈ ℕ
77 adddivflid ⊢ 2 ⁢ K + 1 ∈ ℤ ∧ 1 ∈ ℕ 0 ∧ 4 ∈ ℕ → 1 < 4 ↔ 2 ⁢ K + 1 + 1 4 = 2 ⁢ K + 1
78 72 74 76 77 syl3anc ⊢ K ∈ ℕ 0 → 1 < 4 ↔ 2 ⁢ K + 1 + 1 4 = 2 ⁢ K + 1
79 23 24 mulcld ⊢ K ∈ ℕ 0 → 2 ⁢ K ∈ ℂ
80 49 a1i ⊢ K ∈ ℕ 0 → 4 ≠ 0
81 21 80 reccld ⊢ K ∈ ℕ 0 → 1 4 ∈ ℂ
82 79 14 81 addassd ⊢ K ∈ ℕ 0 → 2 ⁢ K + 1 + 1 4 = 2 ⁢ K + 1 + 1 4
83 df-5 ⊢ 5 = 4 + 1
84 83 oveq1i ⊢ 5 4 = 4 + 1 4
85 ax-1cn ⊢ 1 ∈ ℂ
86 20 85 20 49 divdiri ⊢ 4 + 1 4 = 4 4 + 1 4
87 20 49 dividi ⊢ 4 4 = 1
88 87 oveq1i ⊢ 4 4 + 1 4 = 1 + 1 4
89 84 86 88 3eqtri ⊢ 5 4 = 1 + 1 4
90 89 a1i ⊢ K ∈ ℕ 0 → 5 4 = 1 + 1 4
91 90 eqcomd ⊢ K ∈ ℕ 0 → 1 + 1 4 = 5 4
92 91 oveq2d ⊢ K ∈ ℕ 0 → 2 ⁢ K + 1 + 1 4 = 2 ⁢ K + 5 4
93 82 92 eqtrd ⊢ K ∈ ℕ 0 → 2 ⁢ K + 1 + 1 4 = 2 ⁢ K + 5 4
94 93 fveqeq2d ⊢ K ∈ ℕ 0 → 2 ⁢ K + 1 + 1 4 = 2 ⁢ K + 1 ↔ 2 ⁢ K + 5 4 = 2 ⁢ K + 1
95 78 94 bitrd ⊢ K ∈ ℕ 0 → 1 < 4 ↔ 2 ⁢ K + 5 4 = 2 ⁢ K + 1
96 67 95 mpbii ⊢ K ∈ ℕ 0 → 2 ⁢ K + 5 4 = 2 ⁢ K + 1
97 66 96 eqtrd ⊢ K ∈ ℕ 0 → 8 ⁢ K + 5 4 = 2 ⁢ K + 1
98 48 97 oveq12d ⊢ K ∈ ℕ 0 → 8 ⁢ K + 5 - 1 2 − 8 ⁢ K + 5 4 = 4 ⁢ K + 2 - 2 ⁢ K + 1
99 70 nn0cnd ⊢ K ∈ ℕ 0 → 2 ⁢ K ∈ ℂ
100 35 23 99 14 addsub4d ⊢ K ∈ ℕ 0 → 4 ⁢ K + 2 - 2 ⁢ K + 1 = 4 ⁢ K − 2 ⁢ K + 2 - 1
101 2t2e4 ⊢ 2 ⋅ 2 = 4
102 101 eqcomi ⊢ 4 = 2 ⋅ 2
103 102 a1i ⊢ K ∈ ℕ 0 → 4 = 2 ⋅ 2
104 103 oveq1d ⊢ K ∈ ℕ 0 → 4 ⁢ K = 2 ⋅ 2 ⁢ K
105 23 23 24 mulassd ⊢ K ∈ ℕ 0 → 2 ⋅ 2 ⁢ K = 2 ⁢ 2 ⁢ K
106 104 105 eqtrd ⊢ K ∈ ℕ 0 → 4 ⁢ K = 2 ⁢ 2 ⁢ K
107 106 oveq1d ⊢ K ∈ ℕ 0 → 4 ⁢ K − 2 ⁢ K = 2 ⁢ 2 ⁢ K − 2 ⁢ K
108 2txmxeqx ⊢ 2 ⁢ K ∈ ℂ → 2 ⁢ 2 ⁢ K − 2 ⁢ K = 2 ⁢ K
109 99 108 syl ⊢ K ∈ ℕ 0 → 2 ⁢ 2 ⁢ K − 2 ⁢ K = 2 ⁢ K
110 107 109 eqtrd ⊢ K ∈ ℕ 0 → 4 ⁢ K − 2 ⁢ K = 2 ⁢ K
111 2m1e1 ⊢ 2 − 1 = 1
112 111 a1i ⊢ K ∈ ℕ 0 → 2 − 1 = 1
113 110 112 oveq12d ⊢ K ∈ ℕ 0 → 4 ⁢ K − 2 ⁢ K + 2 - 1 = 2 ⁢ K + 1
114 98 100 113 3eqtrd ⊢ K ∈ ℕ 0 → 8 ⁢ K + 5 - 1 2 − 8 ⁢ K + 5 4 = 2 ⁢ K + 1
115 6 114 sylan9eqr ⊢ K ∈ ℕ 0 ∧ P = 8 ⁢ K + 5 → N = 2 ⁢ K + 1