Metamath Proof Explorer


Theorem 2lgslem3d

Description: Lemma for 2lgslem3d1 . (Contributed by AV, 16-Jul-2021)

Ref Expression
Hypothesis 2lgslem2.n ⊢ N = P − 1 2 − P 4
Assertion 2lgslem3d ⊢ K ∈ ℕ 0 ∧ P = 8 ⁢ K + 7 → N = 2 ⁢ K + 2

Proof

Step Hyp Ref Expression
1 2lgslem2.n ⊢ N = P − 1 2 − P 4
2 oveq1 ⊢ P = 8 ⁢ K + 7 → P − 1 = 8 ⁢ K + 7 - 1
3 2 oveq1d ⊢ P = 8 ⁢ K + 7 → P − 1 2 = 8 ⁢ K + 7 - 1 2
4 fvoveq1 ⊢ P = 8 ⁢ K + 7 → P 4 = 8 ⁢ K + 7 4
5 3 4 oveq12d ⊢ P = 8 ⁢ K + 7 → P − 1 2 − P 4 = 8 ⁢ K + 7 - 1 2 − 8 ⁢ K + 7 4
6 1 5 eqtrid ⊢ P = 8 ⁢ K + 7 → N = 8 ⁢ K + 7 - 1 2 − 8 ⁢ K + 7 4
7 8nn0 ⊢ 8 ∈ ℕ 0
8 7 a1i ⊢ K ∈ ℕ 0 → 8 ∈ ℕ 0
9 id ⊢ K ∈ ℕ 0 → K ∈ ℕ 0
10 8 9 nn0mulcld ⊢ K ∈ ℕ 0 → 8 ⁢ K ∈ ℕ 0
11 10 nn0cnd ⊢ K ∈ ℕ 0 → 8 ⁢ K ∈ ℂ
12 7cn ⊢ 7 ∈ ℂ
13 12 a1i ⊢ K ∈ ℕ 0 → 7 ∈ ℂ
14 1cnd ⊢ K ∈ ℕ 0 → 1 ∈ ℂ
15 11 13 14 addsubassd ⊢ K ∈ ℕ 0 → 8 ⁢ K + 7 - 1 = 8 ⁢ K + 7 - 1
16 4t2e8 ⊢ 4 ⋅ 2 = 8
17 16 eqcomi ⊢ 8 = 4 ⋅ 2
18 17 a1i ⊢ K ∈ ℕ 0 → 8 = 4 ⋅ 2
19 18 oveq1d ⊢ K ∈ ℕ 0 → 8 ⁢ K = 4 ⋅ 2 ⁢ K
20 4cn ⊢ 4 ∈ ℂ
21 20 a1i ⊢ K ∈ ℕ 0 → 4 ∈ ℂ
22 2cn ⊢ 2 ∈ ℂ
23 22 a1i ⊢ K ∈ ℕ 0 → 2 ∈ ℂ
24 nn0cn ⊢ K ∈ ℕ 0 → K ∈ ℂ
25 21 23 24 mul32d ⊢ K ∈ ℕ 0 → 4 ⋅ 2 ⁢ K = 4 ⁢ K ⋅ 2
26 19 25 eqtrd ⊢ K ∈ ℕ 0 → 8 ⁢ K = 4 ⁢ K ⋅ 2
27 7m1e6 ⊢ 7 − 1 = 6
28 27 a1i ⊢ K ∈ ℕ 0 → 7 − 1 = 6
29 26 28 oveq12d ⊢ K ∈ ℕ 0 → 8 ⁢ K + 7 - 1 = 4 ⁢ K ⋅ 2 + 6
30 15 29 eqtrd ⊢ K ∈ ℕ 0 → 8 ⁢ K + 7 - 1 = 4 ⁢ K ⋅ 2 + 6
31 30 oveq1d ⊢ K ∈ ℕ 0 → 8 ⁢ K + 7 - 1 2 = 4 ⁢ K ⋅ 2 + 6 2
32 4nn0 ⊢ 4 ∈ ℕ 0
33 32 a1i ⊢ K ∈ ℕ 0 → 4 ∈ ℕ 0
34 33 9 nn0mulcld ⊢ K ∈ ℕ 0 → 4 ⁢ K ∈ ℕ 0
35 34 nn0cnd ⊢ K ∈ ℕ 0 → 4 ⁢ K ∈ ℂ
36 35 23 mulcld ⊢ K ∈ ℕ 0 → 4 ⁢ K ⋅ 2 ∈ ℂ
37 6cn ⊢ 6 ∈ ℂ
38 37 a1i ⊢ K ∈ ℕ 0 → 6 ∈ ℂ
39 2rp ⊢ 2 ∈ ℝ +
40 39 a1i ⊢ K ∈ ℕ 0 → 2 ∈ ℝ +
41 40 rpcnne0d ⊢ K ∈ ℕ 0 → 2 ∈ ℂ ∧ 2 ≠ 0
42 divdir ⊢ 4 ⁢ K ⋅ 2 ∈ ℂ ∧ 6 ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 → 4 ⁢ K ⋅ 2 + 6 2 = 4 ⁢ K ⋅ 2 2 + 6 2
43 36 38 41 42 syl3anc ⊢ K ∈ ℕ 0 → 4 ⁢ K ⋅ 2 + 6 2 = 4 ⁢ K ⋅ 2 2 + 6 2
44 2ne0 ⊢ 2 ≠ 0
45 44 a1i ⊢ K ∈ ℕ 0 → 2 ≠ 0
46 35 23 45 divcan4d ⊢ K ∈ ℕ 0 → 4 ⁢ K ⋅ 2 2 = 4 ⁢ K
47 3t2e6 ⊢ 3 ⋅ 2 = 6
48 47 eqcomi ⊢ 6 = 3 ⋅ 2
49 48 oveq1i ⊢ 6 2 = 3 ⋅ 2 2
50 3cn ⊢ 3 ∈ ℂ
51 50 22 44 divcan4i ⊢ 3 ⋅ 2 2 = 3
52 49 51 eqtri ⊢ 6 2 = 3
53 52 a1i ⊢ K ∈ ℕ 0 → 6 2 = 3
54 46 53 oveq12d ⊢ K ∈ ℕ 0 → 4 ⁢ K ⋅ 2 2 + 6 2 = 4 ⁢ K + 3
55 31 43 54 3eqtrd ⊢ K ∈ ℕ 0 → 8 ⁢ K + 7 - 1 2 = 4 ⁢ K + 3
56 4ne0 ⊢ 4 ≠ 0
57 20 56 pm3.2i ⊢ 4 ∈ ℂ ∧ 4 ≠ 0
58 57 a1i ⊢ K ∈ ℕ 0 → 4 ∈ ℂ ∧ 4 ≠ 0
59 divdir ⊢ 8 ⁢ K ∈ ℂ ∧ 7 ∈ ℂ ∧ 4 ∈ ℂ ∧ 4 ≠ 0 → 8 ⁢ K + 7 4 = 8 ⁢ K 4 + 7 4
60 11 13 58 59 syl3anc ⊢ K ∈ ℕ 0 → 8 ⁢ K + 7 4 = 8 ⁢ K 4 + 7 4
61 8cn ⊢ 8 ∈ ℂ
62 61 a1i ⊢ K ∈ ℕ 0 → 8 ∈ ℂ
63 div23 ⊢ 8 ∈ ℂ ∧ K ∈ ℂ ∧ 4 ∈ ℂ ∧ 4 ≠ 0 → 8 ⁢ K 4 = 8 4 ⁢ K
64 62 24 58 63 syl3anc ⊢ K ∈ ℕ 0 → 8 ⁢ K 4 = 8 4 ⁢ K
65 17 oveq1i ⊢ 8 4 = 4 ⋅ 2 4
66 22 20 56 divcan3i ⊢ 4 ⋅ 2 4 = 2
67 65 66 eqtri ⊢ 8 4 = 2
68 67 a1i ⊢ K ∈ ℕ 0 → 8 4 = 2
69 68 oveq1d ⊢ K ∈ ℕ 0 → 8 4 ⁢ K = 2 ⁢ K
70 64 69 eqtrd ⊢ K ∈ ℕ 0 → 8 ⁢ K 4 = 2 ⁢ K
71 70 oveq1d ⊢ K ∈ ℕ 0 → 8 ⁢ K 4 + 7 4 = 2 ⁢ K + 7 4
72 60 71 eqtrd ⊢ K ∈ ℕ 0 → 8 ⁢ K + 7 4 = 2 ⁢ K + 7 4
73 72 fveq2d ⊢ K ∈ ℕ 0 → 8 ⁢ K + 7 4 = 2 ⁢ K + 7 4
74 3lt4 ⊢ 3 < 4
75 2nn0 ⊢ 2 ∈ ℕ 0
76 75 a1i ⊢ K ∈ ℕ 0 → 2 ∈ ℕ 0
77 76 9 nn0mulcld ⊢ K ∈ ℕ 0 → 2 ⁢ K ∈ ℕ 0
78 77 nn0zd ⊢ K ∈ ℕ 0 → 2 ⁢ K ∈ ℤ
79 78 peano2zd ⊢ K ∈ ℕ 0 → 2 ⁢ K + 1 ∈ ℤ
80 3nn0 ⊢ 3 ∈ ℕ 0
81 80 a1i ⊢ K ∈ ℕ 0 → 3 ∈ ℕ 0
82 4nn ⊢ 4 ∈ ℕ
83 82 a1i ⊢ K ∈ ℕ 0 → 4 ∈ ℕ
84 adddivflid ⊢ 2 ⁢ K + 1 ∈ ℤ ∧ 3 ∈ ℕ 0 ∧ 4 ∈ ℕ → 3 < 4 ↔ 2 ⁢ K + 1 + 3 4 = 2 ⁢ K + 1
85 79 81 83 84 syl3anc ⊢ K ∈ ℕ 0 → 3 < 4 ↔ 2 ⁢ K + 1 + 3 4 = 2 ⁢ K + 1
86 23 24 mulcld ⊢ K ∈ ℕ 0 → 2 ⁢ K ∈ ℂ
87 50 a1i ⊢ K ∈ ℕ 0 → 3 ∈ ℂ
88 56 a1i ⊢ K ∈ ℕ 0 → 4 ≠ 0
89 87 21 88 divcld ⊢ K ∈ ℕ 0 → 3 4 ∈ ℂ
90 86 14 89 addassd ⊢ K ∈ ℕ 0 → 2 ⁢ K + 1 + 3 4 = 2 ⁢ K + 1 + 3 4
91 4p3e7 ⊢ 4 + 3 = 7
92 91 eqcomi ⊢ 7 = 4 + 3
93 92 oveq1i ⊢ 7 4 = 4 + 3 4
94 20 50 20 56 divdiri ⊢ 4 + 3 4 = 4 4 + 3 4
95 20 56 dividi ⊢ 4 4 = 1
96 95 oveq1i ⊢ 4 4 + 3 4 = 1 + 3 4
97 93 94 96 3eqtri ⊢ 7 4 = 1 + 3 4
98 97 a1i ⊢ K ∈ ℕ 0 → 7 4 = 1 + 3 4
99 98 eqcomd ⊢ K ∈ ℕ 0 → 1 + 3 4 = 7 4
100 99 oveq2d ⊢ K ∈ ℕ 0 → 2 ⁢ K + 1 + 3 4 = 2 ⁢ K + 7 4
101 90 100 eqtrd ⊢ K ∈ ℕ 0 → 2 ⁢ K + 1 + 3 4 = 2 ⁢ K + 7 4
102 101 fveqeq2d ⊢ K ∈ ℕ 0 → 2 ⁢ K + 1 + 3 4 = 2 ⁢ K + 1 ↔ 2 ⁢ K + 7 4 = 2 ⁢ K + 1
103 85 102 bitrd ⊢ K ∈ ℕ 0 → 3 < 4 ↔ 2 ⁢ K + 7 4 = 2 ⁢ K + 1
104 74 103 mpbii ⊢ K ∈ ℕ 0 → 2 ⁢ K + 7 4 = 2 ⁢ K + 1
105 73 104 eqtrd ⊢ K ∈ ℕ 0 → 8 ⁢ K + 7 4 = 2 ⁢ K + 1
106 55 105 oveq12d ⊢ K ∈ ℕ 0 → 8 ⁢ K + 7 - 1 2 − 8 ⁢ K + 7 4 = 4 ⁢ K + 3 - 2 ⁢ K + 1
107 77 nn0cnd ⊢ K ∈ ℕ 0 → 2 ⁢ K ∈ ℂ
108 35 87 107 14 addsub4d ⊢ K ∈ ℕ 0 → 4 ⁢ K + 3 - 2 ⁢ K + 1 = 4 ⁢ K − 2 ⁢ K + 3 - 1
109 2t2e4 ⊢ 2 ⋅ 2 = 4
110 109 eqcomi ⊢ 4 = 2 ⋅ 2
111 110 a1i ⊢ K ∈ ℕ 0 → 4 = 2 ⋅ 2
112 111 oveq1d ⊢ K ∈ ℕ 0 → 4 ⁢ K = 2 ⋅ 2 ⁢ K
113 23 23 24 mulassd ⊢ K ∈ ℕ 0 → 2 ⋅ 2 ⁢ K = 2 ⁢ 2 ⁢ K
114 112 113 eqtrd ⊢ K ∈ ℕ 0 → 4 ⁢ K = 2 ⁢ 2 ⁢ K
115 114 oveq1d ⊢ K ∈ ℕ 0 → 4 ⁢ K − 2 ⁢ K = 2 ⁢ 2 ⁢ K − 2 ⁢ K
116 2txmxeqx ⊢ 2 ⁢ K ∈ ℂ → 2 ⁢ 2 ⁢ K − 2 ⁢ K = 2 ⁢ K
117 107 116 syl ⊢ K ∈ ℕ 0 → 2 ⁢ 2 ⁢ K − 2 ⁢ K = 2 ⁢ K
118 115 117 eqtrd ⊢ K ∈ ℕ 0 → 4 ⁢ K − 2 ⁢ K = 2 ⁢ K
119 3m1e2 ⊢ 3 − 1 = 2
120 119 a1i ⊢ K ∈ ℕ 0 → 3 − 1 = 2
121 118 120 oveq12d ⊢ K ∈ ℕ 0 → 4 ⁢ K − 2 ⁢ K + 3 - 1 = 2 ⁢ K + 2
122 106 108 121 3eqtrd ⊢ K ∈ ℕ 0 → 8 ⁢ K + 7 - 1 2 − 8 ⁢ K + 7 4 = 2 ⁢ K + 2
123 6 122 sylan9eqr ⊢ K ∈ ℕ 0 ∧ P = 8 ⁢ K + 7 → N = 2 ⁢ K + 2