Metamath Proof Explorer


Theorem 2lgsoddprm

Description: The second supplement to the law of quadratic reciprocity for odd primes (common representation, see theorem 9.5 in ApostolNT p. 181): The Legendre symbol for 2 at an odd prime is minus one to the power of the square of the odd prime minus one divided by eight ( ( 2 /L P ) = -1^(((P^2)-1)/8) ). (Contributed by AV, 20-Jul-2021)

Ref Expression
Assertion 2lgsoddprm ⊢ P ∈ ℙ ∖ 2 → 2 / L P = − 1 P 2 − 1 8

Proof

Step Hyp Ref Expression
1 eldifi ⊢ P ∈ ℙ ∖ 2 → P ∈ ℙ
2 2lgs ⊢ P ∈ ℙ → 2 / L P = 1 ↔ P mod 8 ∈ 1 7
3 1 2 syl ⊢ P ∈ ℙ ∖ 2 → 2 / L P = 1 ↔ P mod 8 ∈ 1 7
4 simpl ⊢ 2 / L P = 1 ∧ P mod 8 ∈ 1 7 ∧ P ∈ ℙ ∖ 2 → 2 / L P = 1
5 eqcom ⊢ 1 = − 1 P 2 − 1 8 ↔ − 1 P 2 − 1 8 = 1
6 5 a1i ⊢ P ∈ ℙ ∖ 2 → 1 = − 1 P 2 − 1 8 ↔ − 1 P 2 − 1 8 = 1
7 nnoddn2prm ⊢ P ∈ ℙ ∖ 2 → P ∈ ℕ ∧ ¬ 2 ∥ P
8 nnz ⊢ P ∈ ℕ → P ∈ ℤ
9 8 anim1i ⊢ P ∈ ℕ ∧ ¬ 2 ∥ P → P ∈ ℤ ∧ ¬ 2 ∥ P
10 7 9 syl ⊢ P ∈ ℙ ∖ 2 → P ∈ ℤ ∧ ¬ 2 ∥ P
11 sqoddm1div8z ⊢ P ∈ ℤ ∧ ¬ 2 ∥ P → P 2 − 1 8 ∈ ℤ
12 10 11 syl ⊢ P ∈ ℙ ∖ 2 → P 2 − 1 8 ∈ ℤ
13 m1exp1 ⊢ P 2 − 1 8 ∈ ℤ → − 1 P 2 − 1 8 = 1 ↔ 2 ∥ P 2 − 1 8
14 12 13 syl ⊢ P ∈ ℙ ∖ 2 → − 1 P 2 − 1 8 = 1 ↔ 2 ∥ P 2 − 1 8
15 2lgsoddprmlem4 ⊢ P ∈ ℤ ∧ ¬ 2 ∥ P → 2 ∥ P 2 − 1 8 ↔ P mod 8 ∈ 1 7
16 10 15 syl ⊢ P ∈ ℙ ∖ 2 → 2 ∥ P 2 − 1 8 ↔ P mod 8 ∈ 1 7
17 6 14 16 3bitrd ⊢ P ∈ ℙ ∖ 2 → 1 = − 1 P 2 − 1 8 ↔ P mod 8 ∈ 1 7
18 17 biimparc ⊢ P mod 8 ∈ 1 7 ∧ P ∈ ℙ ∖ 2 → 1 = − 1 P 2 − 1 8
19 18 adantl ⊢ 2 / L P = 1 ∧ P mod 8 ∈ 1 7 ∧ P ∈ ℙ ∖ 2 → 1 = − 1 P 2 − 1 8
20 4 19 eqtrd ⊢ 2 / L P = 1 ∧ P mod 8 ∈ 1 7 ∧ P ∈ ℙ ∖ 2 → 2 / L P = − 1 P 2 − 1 8
21 20 exp32 ⊢ 2 / L P = 1 → P mod 8 ∈ 1 7 → P ∈ ℙ ∖ 2 → 2 / L P = − 1 P 2 − 1 8
22 2z ⊢ 2 ∈ ℤ
23 prmz ⊢ P ∈ ℙ → P ∈ ℤ
24 1 23 syl ⊢ P ∈ ℙ ∖ 2 → P ∈ ℤ
25 lgscl1 ⊢ 2 ∈ ℤ ∧ P ∈ ℤ → 2 / L P ∈ − 1 0 1
26 22 24 25 sylancr ⊢ P ∈ ℙ ∖ 2 → 2 / L P ∈ − 1 0 1
27 ovex ⊢ 2 / L P ∈ V
28 27 eltp ⊢ 2 / L P ∈ − 1 0 1 ↔ 2 / L P = − 1 ∨ 2 / L P = 0 ∨ 2 / L P = 1
29 simpl ⊢ 2 / L P = − 1 ∧ P ∈ ℙ ∖ 2 ∧ ¬ P mod 8 ∈ 1 7 → 2 / L P = − 1
30 16 notbid ⊢ P ∈ ℙ ∖ 2 → ¬ 2 ∥ P 2 − 1 8 ↔ ¬ P mod 8 ∈ 1 7
31 30 biimpar ⊢ P ∈ ℙ ∖ 2 ∧ ¬ P mod 8 ∈ 1 7 → ¬ 2 ∥ P 2 − 1 8
32 m1expo ⊢ P 2 − 1 8 ∈ ℤ ∧ ¬ 2 ∥ P 2 − 1 8 → − 1 P 2 − 1 8 = − 1
33 12 31 32 syl2an2r ⊢ P ∈ ℙ ∖ 2 ∧ ¬ P mod 8 ∈ 1 7 → − 1 P 2 − 1 8 = − 1
34 33 eqcomd ⊢ P ∈ ℙ ∖ 2 ∧ ¬ P mod 8 ∈ 1 7 → − 1 = − 1 P 2 − 1 8
35 34 adantl ⊢ 2 / L P = − 1 ∧ P ∈ ℙ ∖ 2 ∧ ¬ P mod 8 ∈ 1 7 → − 1 = − 1 P 2 − 1 8
36 29 35 eqtrd ⊢ 2 / L P = − 1 ∧ P ∈ ℙ ∖ 2 ∧ ¬ P mod 8 ∈ 1 7 → 2 / L P = − 1 P 2 − 1 8
37 36 a1d ⊢ 2 / L P = − 1 ∧ P ∈ ℙ ∖ 2 ∧ ¬ P mod 8 ∈ 1 7 → ¬ 2 / L P = 1 → 2 / L P = − 1 P 2 − 1 8
38 37 exp32 ⊢ 2 / L P = − 1 → P ∈ ℙ ∖ 2 → ¬ P mod 8 ∈ 1 7 → ¬ 2 / L P = 1 → 2 / L P = − 1 P 2 − 1 8
39 eldifsn ⊢ P ∈ ℙ ∖ 2 ↔ P ∈ ℙ ∧ P ≠ 2
40 simpr ⊢ P ∈ ℙ ∧ P ≠ 2 → P ≠ 2
41 40 necomd ⊢ P ∈ ℙ ∧ P ≠ 2 → 2 ≠ P
42 39 41 sylbi ⊢ P ∈ ℙ ∖ 2 → 2 ≠ P
43 2prm ⊢ 2 ∈ ℙ
44 prmrp ⊢ 2 ∈ ℙ ∧ P ∈ ℙ → 2 gcd P = 1 ↔ 2 ≠ P
45 43 1 44 sylancr ⊢ P ∈ ℙ ∖ 2 → 2 gcd P = 1 ↔ 2 ≠ P
46 42 45 mpbird ⊢ P ∈ ℙ ∖ 2 → 2 gcd P = 1
47 lgsne0 ⊢ 2 ∈ ℤ ∧ P ∈ ℤ → 2 / L P ≠ 0 ↔ 2 gcd P = 1
48 22 24 47 sylancr ⊢ P ∈ ℙ ∖ 2 → 2 / L P ≠ 0 ↔ 2 gcd P = 1
49 46 48 mpbird ⊢ P ∈ ℙ ∖ 2 → 2 / L P ≠ 0
50 eqneqall ⊢ 2 / L P = 0 → 2 / L P ≠ 0 → ¬ P mod 8 ∈ 1 7 → ¬ 2 / L P = 1 → 2 / L P = − 1 P 2 − 1 8
51 49 50 syl5 ⊢ 2 / L P = 0 → P ∈ ℙ ∖ 2 → ¬ P mod 8 ∈ 1 7 → ¬ 2 / L P = 1 → 2 / L P = − 1 P 2 − 1 8
52 pm2.24 ⊢ 2 / L P = 1 → ¬ 2 / L P = 1 → 2 / L P = − 1 P 2 − 1 8
53 52 2a1d ⊢ 2 / L P = 1 → P ∈ ℙ ∖ 2 → ¬ P mod 8 ∈ 1 7 → ¬ 2 / L P = 1 → 2 / L P = − 1 P 2 − 1 8
54 38 51 53 3jaoi ⊢ 2 / L P = − 1 ∨ 2 / L P = 0 ∨ 2 / L P = 1 → P ∈ ℙ ∖ 2 → ¬ P mod 8 ∈ 1 7 → ¬ 2 / L P = 1 → 2 / L P = − 1 P 2 − 1 8
55 28 54 sylbi ⊢ 2 / L P ∈ − 1 0 1 → P ∈ ℙ ∖ 2 → ¬ P mod 8 ∈ 1 7 → ¬ 2 / L P = 1 → 2 / L P = − 1 P 2 − 1 8
56 26 55 mpcom ⊢ P ∈ ℙ ∖ 2 → ¬ P mod 8 ∈ 1 7 → ¬ 2 / L P = 1 → 2 / L P = − 1 P 2 − 1 8
57 56 com13 ⊢ ¬ 2 / L P = 1 → ¬ P mod 8 ∈ 1 7 → P ∈ ℙ ∖ 2 → 2 / L P = − 1 P 2 − 1 8
58 21 57 bija ⊢ 2 / L P = 1 ↔ P mod 8 ∈ 1 7 → P ∈ ℙ ∖ 2 → 2 / L P = − 1 P 2 − 1 8
59 3 58 mpcom ⊢ P ∈ ℙ ∖ 2 → 2 / L P = − 1 P 2 − 1 8