Metamath Proof Explorer


Theorem 2lgsoddprmlem3b

Description: Lemma 2 for 2lgsoddprmlem3 . (Contributed by AV, 20-Jul-2021)

Ref Expression
Assertion 2lgsoddprmlem3b ⊢ 3 2 − 1 8 = 1

Proof

Step Hyp Ref Expression
1 sq3 ⊢ 3 2 = 9
2 1 oveq1i ⊢ 3 2 − 1 = 9 − 1
3 9m1e8 ⊢ 9 − 1 = 8
4 2 3 eqtri ⊢ 3 2 − 1 = 8
5 4 oveq1i ⊢ 3 2 − 1 8 = 8 8
6 8cn ⊢ 8 ∈ ℂ
7 0re ⊢ 0 ∈ ℝ
8 8pos ⊢ 0 < 8
9 7 8 gtneii ⊢ 8 ≠ 0
10 6 9 dividi ⊢ 8 8 = 1
11 5 10 eqtri ⊢ 3 2 − 1 8 = 1