Metamath Proof Explorer


Theorem 2ndfcl

Description: The second projection functor is a functor onto the right argument. (Contributed by Mario Carneiro, 11-Jan-2017)

Ref Expression
Hypotheses 1stfcl.t ⊢ T = C × c D
1stfcl.c ⊢ φ → C ∈ Cat
1stfcl.d ⊢ φ → D ∈ Cat
2ndfcl.p ⊢ Q = C 2 nd F D
Assertion 2ndfcl ⊢ φ → Q ∈ T Func D

Proof

Step Hyp Ref Expression
1 1stfcl.t ⊢ T = C × c D
2 1stfcl.c ⊢ φ → C ∈ Cat
3 1stfcl.d ⊢ φ → D ∈ Cat
4 2ndfcl.p ⊢ Q = C 2 nd F D
5 eqid ⊢ Base C = Base C
6 eqid ⊢ Base D = Base D
7 1 5 6 xpcbas ⊢ Base C × Base D = Base T
8 eqid ⊢ Hom ⁡ T = Hom ⁡ T
9 1 7 8 2 3 4 2ndfval ⊢ φ → Q = 2 nd ↾ Base C × Base D x ∈ Base C × Base D , y ∈ Base C × Base D ⟼ 2 nd ↾ x Hom ⁡ T y
10 fo2nd ⊢ 2 nd : V ⟶ onto V
11 fofun ⊢ 2 nd : V ⟶ onto V → Fun ⁡ 2 nd
12 10 11 ax-mp ⊢ Fun ⁡ 2 nd
13 fvex ⊢ Base C ∈ V
14 fvex ⊢ Base D ∈ V
15 13 14 xpex ⊢ Base C × Base D ∈ V
16 resfunexg ⊢ Fun ⁡ 2 nd ∧ Base C × Base D ∈ V → 2 nd ↾ Base C × Base D ∈ V
17 12 15 16 mp2an ⊢ 2 nd ↾ Base C × Base D ∈ V
18 15 15 mpoex ⊢ x ∈ Base C × Base D , y ∈ Base C × Base D ⟼ 2 nd ↾ x Hom ⁡ T y ∈ V
19 17 18 op2ndd ⊢ Q = 2 nd ↾ Base C × Base D x ∈ Base C × Base D , y ∈ Base C × Base D ⟼ 2 nd ↾ x Hom ⁡ T y → 2 nd ⁡ Q = x ∈ Base C × Base D , y ∈ Base C × Base D ⟼ 2 nd ↾ x Hom ⁡ T y
20 9 19 syl ⊢ φ → 2 nd ⁡ Q = x ∈ Base C × Base D , y ∈ Base C × Base D ⟼ 2 nd ↾ x Hom ⁡ T y
21 20 opeq2d ⊢ φ → 2 nd ↾ Base C × Base D 2 nd ⁡ Q = 2 nd ↾ Base C × Base D x ∈ Base C × Base D , y ∈ Base C × Base D ⟼ 2 nd ↾ x Hom ⁡ T y
22 9 21 eqtr4d ⊢ φ → Q = 2 nd ↾ Base C × Base D 2 nd ⁡ Q
23 eqid ⊢ Hom ⁡ D = Hom ⁡ D
24 eqid ⊢ Id ⁡ T = Id ⁡ T
25 eqid ⊢ Id ⁡ D = Id ⁡ D
26 eqid ⊢ comp ⁡ T = comp ⁡ T
27 eqid ⊢ comp ⁡ D = comp ⁡ D
28 1 2 3 xpccat ⊢ φ → T ∈ Cat
29 f2ndres ⊢ 2 nd ↾ Base C × Base D : Base C × Base D ⟶ Base D
30 29 a1i ⊢ φ → 2 nd ↾ Base C × Base D : Base C × Base D ⟶ Base D
31 eqid ⊢ x ∈ Base C × Base D , y ∈ Base C × Base D ⟼ 2 nd ↾ x Hom ⁡ T y = x ∈ Base C × Base D , y ∈ Base C × Base D ⟼ 2 nd ↾ x Hom ⁡ T y
32 ovex ⊢ x Hom ⁡ T y ∈ V
33 resfunexg ⊢ Fun ⁡ 2 nd ∧ x Hom ⁡ T y ∈ V → 2 nd ↾ x Hom ⁡ T y ∈ V
34 12 32 33 mp2an ⊢ 2 nd ↾ x Hom ⁡ T y ∈ V
35 31 34 fnmpoi ⊢ x ∈ Base C × Base D , y ∈ Base C × Base D ⟼ 2 nd ↾ x Hom ⁡ T y Fn Base C × Base D × Base C × Base D
36 20 fneq1d ⊢ φ → 2 nd ⁡ Q Fn Base C × Base D × Base C × Base D ↔ x ∈ Base C × Base D , y ∈ Base C × Base D ⟼ 2 nd ↾ x Hom ⁡ T y Fn Base C × Base D × Base C × Base D
37 35 36 mpbiri ⊢ φ → 2 nd ⁡ Q Fn Base C × Base D × Base C × Base D
38 f2ndres ⊢ 2 nd ↾ 1 st ⁡ x Hom ⁡ C 1 st ⁡ y × 2 nd ⁡ x Hom ⁡ D 2 nd ⁡ y : 1 st ⁡ x Hom ⁡ C 1 st ⁡ y × 2 nd ⁡ x Hom ⁡ D 2 nd ⁡ y ⟶ 2 nd ⁡ x Hom ⁡ D 2 nd ⁡ y
39 2 adantr ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D → C ∈ Cat
40 3 adantr ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D → D ∈ Cat
41 simprl ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D → x ∈ Base C × Base D
42 simprr ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D → y ∈ Base C × Base D
43 1 7 8 39 40 4 41 42 2ndf2 ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D → x 2 nd ⁡ Q y = 2 nd ↾ x Hom ⁡ T y
44 eqid ⊢ Hom ⁡ C = Hom ⁡ C
45 1 7 44 23 8 41 42 xpchom ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D → x Hom ⁡ T y = 1 st ⁡ x Hom ⁡ C 1 st ⁡ y × 2 nd ⁡ x Hom ⁡ D 2 nd ⁡ y
46 45 reseq2d ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D → 2 nd ↾ x Hom ⁡ T y = 2 nd ↾ 1 st ⁡ x Hom ⁡ C 1 st ⁡ y × 2 nd ⁡ x Hom ⁡ D 2 nd ⁡ y
47 43 46 eqtrd ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D → x 2 nd ⁡ Q y = 2 nd ↾ 1 st ⁡ x Hom ⁡ C 1 st ⁡ y × 2 nd ⁡ x Hom ⁡ D 2 nd ⁡ y
48 47 feq1d ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D → x 2 nd ⁡ Q y : 1 st ⁡ x Hom ⁡ C 1 st ⁡ y × 2 nd ⁡ x Hom ⁡ D 2 nd ⁡ y ⟶ 2 nd ⁡ x Hom ⁡ D 2 nd ⁡ y ↔ 2 nd ↾ 1 st ⁡ x Hom ⁡ C 1 st ⁡ y × 2 nd ⁡ x Hom ⁡ D 2 nd ⁡ y : 1 st ⁡ x Hom ⁡ C 1 st ⁡ y × 2 nd ⁡ x Hom ⁡ D 2 nd ⁡ y ⟶ 2 nd ⁡ x Hom ⁡ D 2 nd ⁡ y
49 38 48 mpbiri ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D → x 2 nd ⁡ Q y : 1 st ⁡ x Hom ⁡ C 1 st ⁡ y × 2 nd ⁡ x Hom ⁡ D 2 nd ⁡ y ⟶ 2 nd ⁡ x Hom ⁡ D 2 nd ⁡ y
50 fvres ⊢ x ∈ Base C × Base D → 2 nd ↾ Base C × Base D ⁡ x = 2 nd ⁡ x
51 50 ad2antrl ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D → 2 nd ↾ Base C × Base D ⁡ x = 2 nd ⁡ x
52 fvres ⊢ y ∈ Base C × Base D → 2 nd ↾ Base C × Base D ⁡ y = 2 nd ⁡ y
53 52 ad2antll ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D → 2 nd ↾ Base C × Base D ⁡ y = 2 nd ⁡ y
54 51 53 oveq12d ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D → 2 nd ↾ Base C × Base D ⁡ x Hom ⁡ D 2 nd ↾ Base C × Base D ⁡ y = 2 nd ⁡ x Hom ⁡ D 2 nd ⁡ y
55 45 54 feq23d ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D → x 2 nd ⁡ Q y : x Hom ⁡ T y ⟶ 2 nd ↾ Base C × Base D ⁡ x Hom ⁡ D 2 nd ↾ Base C × Base D ⁡ y ↔ x 2 nd ⁡ Q y : 1 st ⁡ x Hom ⁡ C 1 st ⁡ y × 2 nd ⁡ x Hom ⁡ D 2 nd ⁡ y ⟶ 2 nd ⁡ x Hom ⁡ D 2 nd ⁡ y
56 49 55 mpbird ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D → x 2 nd ⁡ Q y : x Hom ⁡ T y ⟶ 2 nd ↾ Base C × Base D ⁡ x Hom ⁡ D 2 nd ↾ Base C × Base D ⁡ y
57 28 adantr ⊢ φ ∧ x ∈ Base C × Base D → T ∈ Cat
58 simpr ⊢ φ ∧ x ∈ Base C × Base D → x ∈ Base C × Base D
59 7 8 24 57 58 catidcl ⊢ φ ∧ x ∈ Base C × Base D → Id ⁡ T ⁡ x ∈ x Hom ⁡ T x
60 59 fvresd ⊢ φ ∧ x ∈ Base C × Base D → 2 nd ↾ x Hom ⁡ T x ⁡ Id ⁡ T ⁡ x = 2 nd ⁡ Id ⁡ T ⁡ x
61 1st2nd2 ⊢ x ∈ Base C × Base D → x = 1 st ⁡ x 2 nd ⁡ x
62 61 adantl ⊢ φ ∧ x ∈ Base C × Base D → x = 1 st ⁡ x 2 nd ⁡ x
63 62 fveq2d ⊢ φ ∧ x ∈ Base C × Base D → Id ⁡ T ⁡ x = Id ⁡ T ⁡ 1 st ⁡ x 2 nd ⁡ x
64 2 adantr ⊢ φ ∧ x ∈ Base C × Base D → C ∈ Cat
65 3 adantr ⊢ φ ∧ x ∈ Base C × Base D → D ∈ Cat
66 eqid ⊢ Id ⁡ C = Id ⁡ C
67 xp1st ⊢ x ∈ Base C × Base D → 1 st ⁡ x ∈ Base C
68 67 adantl ⊢ φ ∧ x ∈ Base C × Base D → 1 st ⁡ x ∈ Base C
69 xp2nd ⊢ x ∈ Base C × Base D → 2 nd ⁡ x ∈ Base D
70 69 adantl ⊢ φ ∧ x ∈ Base C × Base D → 2 nd ⁡ x ∈ Base D
71 1 64 65 5 6 66 25 24 68 70 xpcid ⊢ φ ∧ x ∈ Base C × Base D → Id ⁡ T ⁡ 1 st ⁡ x 2 nd ⁡ x = Id ⁡ C ⁡ 1 st ⁡ x Id ⁡ D ⁡ 2 nd ⁡ x
72 63 71 eqtrd ⊢ φ ∧ x ∈ Base C × Base D → Id ⁡ T ⁡ x = Id ⁡ C ⁡ 1 st ⁡ x Id ⁡ D ⁡ 2 nd ⁡ x
73 fvex ⊢ Id ⁡ C ⁡ 1 st ⁡ x ∈ V
74 fvex ⊢ Id ⁡ D ⁡ 2 nd ⁡ x ∈ V
75 73 74 op2ndd ⊢ Id ⁡ T ⁡ x = Id ⁡ C ⁡ 1 st ⁡ x Id ⁡ D ⁡ 2 nd ⁡ x → 2 nd ⁡ Id ⁡ T ⁡ x = Id ⁡ D ⁡ 2 nd ⁡ x
76 72 75 syl ⊢ φ ∧ x ∈ Base C × Base D → 2 nd ⁡ Id ⁡ T ⁡ x = Id ⁡ D ⁡ 2 nd ⁡ x
77 60 76 eqtrd ⊢ φ ∧ x ∈ Base C × Base D → 2 nd ↾ x Hom ⁡ T x ⁡ Id ⁡ T ⁡ x = Id ⁡ D ⁡ 2 nd ⁡ x
78 1 7 8 64 65 4 58 58 2ndf2 ⊢ φ ∧ x ∈ Base C × Base D → x 2 nd ⁡ Q x = 2 nd ↾ x Hom ⁡ T x
79 78 fveq1d ⊢ φ ∧ x ∈ Base C × Base D → x 2 nd ⁡ Q x ⁡ Id ⁡ T ⁡ x = 2 nd ↾ x Hom ⁡ T x ⁡ Id ⁡ T ⁡ x
80 50 adantl ⊢ φ ∧ x ∈ Base C × Base D → 2 nd ↾ Base C × Base D ⁡ x = 2 nd ⁡ x
81 80 fveq2d ⊢ φ ∧ x ∈ Base C × Base D → Id ⁡ D ⁡ 2 nd ↾ Base C × Base D ⁡ x = Id ⁡ D ⁡ 2 nd ⁡ x
82 77 79 81 3eqtr4d ⊢ φ ∧ x ∈ Base C × Base D → x 2 nd ⁡ Q x ⁡ Id ⁡ T ⁡ x = Id ⁡ D ⁡ 2 nd ↾ Base C × Base D ⁡ x
83 28 3ad2ant1 ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → T ∈ Cat
84 simp21 ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → x ∈ Base C × Base D
85 simp22 ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → y ∈ Base C × Base D
86 simp23 ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → z ∈ Base C × Base D
87 simp3l ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → f ∈ x Hom ⁡ T y
88 simp3r ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → g ∈ y Hom ⁡ T z
89 7 8 26 83 84 85 86 87 88 catcocl ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → g x y comp ⁡ T z f ∈ x Hom ⁡ T z
90 89 fvresd ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → 2 nd ↾ x Hom ⁡ T z ⁡ g x y comp ⁡ T z f = 2 nd ⁡ g x y comp ⁡ T z f
91 1 7 8 26 84 85 86 87 88 27 xpcco2nd ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → 2 nd ⁡ g x y comp ⁡ T z f = 2 nd ⁡ g 2 nd ⁡ x 2 nd ⁡ y comp ⁡ D 2 nd ⁡ z 2 nd ⁡ f
92 90 91 eqtrd ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → 2 nd ↾ x Hom ⁡ T z ⁡ g x y comp ⁡ T z f = 2 nd ⁡ g 2 nd ⁡ x 2 nd ⁡ y comp ⁡ D 2 nd ⁡ z 2 nd ⁡ f
93 2 3ad2ant1 ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → C ∈ Cat
94 3 3ad2ant1 ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → D ∈ Cat
95 1 7 8 93 94 4 84 86 2ndf2 ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → x 2 nd ⁡ Q z = 2 nd ↾ x Hom ⁡ T z
96 95 fveq1d ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → x 2 nd ⁡ Q z ⁡ g x y comp ⁡ T z f = 2 nd ↾ x Hom ⁡ T z ⁡ g x y comp ⁡ T z f
97 84 fvresd ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → 2 nd ↾ Base C × Base D ⁡ x = 2 nd ⁡ x
98 85 fvresd ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → 2 nd ↾ Base C × Base D ⁡ y = 2 nd ⁡ y
99 97 98 opeq12d ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → 2 nd ↾ Base C × Base D ⁡ x 2 nd ↾ Base C × Base D ⁡ y = 2 nd ⁡ x 2 nd ⁡ y
100 86 fvresd ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → 2 nd ↾ Base C × Base D ⁡ z = 2 nd ⁡ z
101 99 100 oveq12d ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → 2 nd ↾ Base C × Base D ⁡ x 2 nd ↾ Base C × Base D ⁡ y comp ⁡ D 2 nd ↾ Base C × Base D ⁡ z = 2 nd ⁡ x 2 nd ⁡ y comp ⁡ D 2 nd ⁡ z
102 1 7 8 93 94 4 85 86 2ndf2 ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → y 2 nd ⁡ Q z = 2 nd ↾ y Hom ⁡ T z
103 102 fveq1d ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → y 2 nd ⁡ Q z ⁡ g = 2 nd ↾ y Hom ⁡ T z ⁡ g
104 88 fvresd ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → 2 nd ↾ y Hom ⁡ T z ⁡ g = 2 nd ⁡ g
105 103 104 eqtrd ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → y 2 nd ⁡ Q z ⁡ g = 2 nd ⁡ g
106 1 7 8 93 94 4 84 85 2ndf2 ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → x 2 nd ⁡ Q y = 2 nd ↾ x Hom ⁡ T y
107 106 fveq1d ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → x 2 nd ⁡ Q y ⁡ f = 2 nd ↾ x Hom ⁡ T y ⁡ f
108 87 fvresd ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → 2 nd ↾ x Hom ⁡ T y ⁡ f = 2 nd ⁡ f
109 107 108 eqtrd ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → x 2 nd ⁡ Q y ⁡ f = 2 nd ⁡ f
110 101 105 109 oveq123d ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → y 2 nd ⁡ Q z ⁡ g 2 nd ↾ Base C × Base D ⁡ x 2 nd ↾ Base C × Base D ⁡ y comp ⁡ D 2 nd ↾ Base C × Base D ⁡ z x 2 nd ⁡ Q y ⁡ f = 2 nd ⁡ g 2 nd ⁡ x 2 nd ⁡ y comp ⁡ D 2 nd ⁡ z 2 nd ⁡ f
111 92 96 110 3eqtr4d ⊢ φ ∧ x ∈ Base C × Base D ∧ y ∈ Base C × Base D ∧ z ∈ Base C × Base D ∧ f ∈ x Hom ⁡ T y ∧ g ∈ y Hom ⁡ T z → x 2 nd ⁡ Q z ⁡ g x y comp ⁡ T z f = y 2 nd ⁡ Q z ⁡ g 2 nd ↾ Base C × Base D ⁡ x 2 nd ↾ Base C × Base D ⁡ y comp ⁡ D 2 nd ↾ Base C × Base D ⁡ z x 2 nd ⁡ Q y ⁡ f
112 7 6 8 23 24 25 26 27 28 3 30 37 56 82 111 isfuncd ⊢ φ → 2 nd ↾ Base C × Base D T Func D 2 nd ⁡ Q
113 df-br ⊢ 2 nd ↾ Base C × Base D T Func D 2 nd ⁡ Q ↔ 2 nd ↾ Base C × Base D 2 nd ⁡ Q ∈ T Func D
114 112 113 sylib ⊢ φ → 2 nd ↾ Base C × Base D 2 nd ⁡ Q ∈ T Func D
115 22 114 eqeltrd ⊢ φ → Q ∈ T Func D