Metamath Proof Explorer


Theorem 2sq2

Description: 2 is the sum of squares of two nonnegative integers iff the two integers are 1 . (Contributed by AV, 19-Jun-2023)

Ref Expression
Assertion 2sq2 ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → A 2 + B 2 = 2 ↔ A = 1 ∧ B = 1

Proof

Step Hyp Ref Expression
1 nn0sqcl ⊢ A ∈ ℕ 0 → A 2 ∈ ℕ 0
2 nn0sqcl ⊢ B ∈ ℕ 0 → B 2 ∈ ℕ 0
3 2 nn0red ⊢ B ∈ ℕ 0 → B 2 ∈ ℝ
4 1 3 anim12ci ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → B 2 ∈ ℝ ∧ A 2 ∈ ℕ 0
5 4 adantr ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ A 2 + B 2 = 2 → B 2 ∈ ℝ ∧ A 2 ∈ ℕ 0
6 nn0addge2 ⊢ B 2 ∈ ℝ ∧ A 2 ∈ ℕ 0 → B 2 ≤ A 2 + B 2
7 5 6 syl ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ A 2 + B 2 = 2 → B 2 ≤ A 2 + B 2
8 breq2 ⊢ A 2 + B 2 = 2 → B 2 ≤ A 2 + B 2 ↔ B 2 ≤ 2
9 8 adantl ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ A 2 + B 2 = 2 → B 2 ≤ A 2 + B 2 ↔ B 2 ≤ 2
10 2 ad2antlr ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ A 2 + B 2 = 2 → B 2 ∈ ℕ 0
11 nn0le2is012 ⊢ B 2 ∈ ℕ 0 ∧ B 2 ≤ 2 → B 2 = 0 ∨ B 2 = 1 ∨ B 2 = 2
12 11 ex ⊢ B 2 ∈ ℕ 0 → B 2 ≤ 2 → B 2 = 0 ∨ B 2 = 1 ∨ B 2 = 2
13 10 12 syl ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ A 2 + B 2 = 2 → B 2 ≤ 2 → B 2 = 0 ∨ B 2 = 1 ∨ B 2 = 2
14 oveq2 ⊢ B 2 = 0 → A 2 + B 2 = A 2 + 0
15 14 eqeq1d ⊢ B 2 = 0 → A 2 + B 2 = 2 ↔ A 2 + 0 = 2
16 15 adantl ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ B 2 = 0 → A 2 + B 2 = 2 ↔ A 2 + 0 = 2
17 1 nn0cnd ⊢ A ∈ ℕ 0 → A 2 ∈ ℂ
18 17 addridd ⊢ A ∈ ℕ 0 → A 2 + 0 = A 2
19 18 adantr ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → A 2 + 0 = A 2
20 19 eqeq1d ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → A 2 + 0 = 2 ↔ A 2 = 2
21 1 nn0red ⊢ A ∈ ℕ 0 → A 2 ∈ ℝ
22 nn0re ⊢ A ∈ ℕ 0 → A ∈ ℝ
23 22 sqge0d ⊢ A ∈ ℕ 0 → 0 ≤ A 2
24 2nn0 ⊢ 2 ∈ ℕ 0
25 24 a1i ⊢ A ∈ ℕ 0 → 2 ∈ ℕ 0
26 25 nn0red ⊢ A ∈ ℕ 0 → 2 ∈ ℝ
27 0le2 ⊢ 0 ≤ 2
28 27 a1i ⊢ A ∈ ℕ 0 → 0 ≤ 2
29 sqrt11 ⊢ A 2 ∈ ℝ ∧ 0 ≤ A 2 ∧ 2 ∈ ℝ ∧ 0 ≤ 2 → A 2 = 2 ↔ A 2 = 2
30 21 23 26 28 29 syl22anc ⊢ A ∈ ℕ 0 → A 2 = 2 ↔ A 2 = 2
31 nn0ge0 ⊢ A ∈ ℕ 0 → 0 ≤ A
32 22 31 sqrtsqd ⊢ A ∈ ℕ 0 → A 2 = A
33 32 eqeq1d ⊢ A ∈ ℕ 0 → A 2 = 2 ↔ A = 2
34 sqrt2irr ⊢ 2 ∉ ℚ
35 df-nel ⊢ 2 ∉ ℚ ↔ ¬ 2 ∈ ℚ
36 id ⊢ 2 = A → 2 = A
37 36 eqcoms ⊢ A = 2 → 2 = A
38 37 eleq1d ⊢ A = 2 → 2 ∈ ℚ ↔ A ∈ ℚ
39 38 notbid ⊢ A = 2 → ¬ 2 ∈ ℚ ↔ ¬ A ∈ ℚ
40 39 adantl ⊢ A ∈ ℕ 0 ∧ A = 2 → ¬ 2 ∈ ℚ ↔ ¬ A ∈ ℚ
41 nn0z ⊢ A ∈ ℕ 0 → A ∈ ℤ
42 zq ⊢ A ∈ ℤ → A ∈ ℚ
43 41 42 syl ⊢ A ∈ ℕ 0 → A ∈ ℚ
44 43 pm2.24d ⊢ A ∈ ℕ 0 → ¬ A ∈ ℚ → A = 1 ∧ B = 1
45 44 adantr ⊢ A ∈ ℕ 0 ∧ A = 2 → ¬ A ∈ ℚ → A = 1 ∧ B = 1
46 40 45 sylbid ⊢ A ∈ ℕ 0 ∧ A = 2 → ¬ 2 ∈ ℚ → A = 1 ∧ B = 1
47 46 com12 ⊢ ¬ 2 ∈ ℚ → A ∈ ℕ 0 ∧ A = 2 → A = 1 ∧ B = 1
48 47 expd ⊢ ¬ 2 ∈ ℚ → A ∈ ℕ 0 → A = 2 → A = 1 ∧ B = 1
49 35 48 sylbi ⊢ 2 ∉ ℚ → A ∈ ℕ 0 → A = 2 → A = 1 ∧ B = 1
50 34 49 ax-mp ⊢ A ∈ ℕ 0 → A = 2 → A = 1 ∧ B = 1
51 33 50 sylbid ⊢ A ∈ ℕ 0 → A 2 = 2 → A = 1 ∧ B = 1
52 30 51 sylbird ⊢ A ∈ ℕ 0 → A 2 = 2 → A = 1 ∧ B = 1
53 52 adantr ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → A 2 = 2 → A = 1 ∧ B = 1
54 20 53 sylbid ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → A 2 + 0 = 2 → A = 1 ∧ B = 1
55 54 adantr ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ B 2 = 0 → A 2 + 0 = 2 → A = 1 ∧ B = 1
56 16 55 sylbid ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ B 2 = 0 → A 2 + B 2 = 2 → A = 1 ∧ B = 1
57 56 impancom ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ A 2 + B 2 = 2 → B 2 = 0 → A = 1 ∧ B = 1
58 oveq2 ⊢ B 2 = 1 → A 2 + B 2 = A 2 + 1
59 58 eqeq1d ⊢ B 2 = 1 → A 2 + B 2 = 2 ↔ A 2 + 1 = 2
60 2cnd ⊢ A ∈ ℕ 0 → 2 ∈ ℂ
61 1cnd ⊢ A ∈ ℕ 0 → 1 ∈ ℂ
62 60 61 17 3jca ⊢ A ∈ ℕ 0 → 2 ∈ ℂ ∧ 1 ∈ ℂ ∧ A 2 ∈ ℂ
63 62 adantr ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → 2 ∈ ℂ ∧ 1 ∈ ℂ ∧ A 2 ∈ ℂ
64 subadd2 ⊢ 2 ∈ ℂ ∧ 1 ∈ ℂ ∧ A 2 ∈ ℂ → 2 − 1 = A 2 ↔ A 2 + 1 = 2
65 63 64 syl ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → 2 − 1 = A 2 ↔ A 2 + 1 = 2
66 65 bicomd ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → A 2 + 1 = 2 ↔ 2 − 1 = A 2
67 59 66 sylan9bbr ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ B 2 = 1 → A 2 + B 2 = 2 ↔ 2 − 1 = A 2
68 nn0sqeq1 ⊢ B ∈ ℕ 0 ∧ B 2 = 1 → B = 1
69 68 ex ⊢ B ∈ ℕ 0 → B 2 = 1 → B = 1
70 69 adantl ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → B 2 = 1 → B = 1
71 2m1e1 ⊢ 2 − 1 = 1
72 71 a1i ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → 2 − 1 = 1
73 72 eqeq1d ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → 2 − 1 = A 2 ↔ 1 = A 2
74 eqcom ⊢ 1 = A 2 ↔ A 2 = 1
75 73 74 bitrdi ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → 2 − 1 = A 2 ↔ A 2 = 1
76 nn0sqeq1 ⊢ A ∈ ℕ 0 ∧ A 2 = 1 → A = 1
77 76 ex ⊢ A ∈ ℕ 0 → A 2 = 1 → A = 1
78 77 adantr ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → A 2 = 1 → A = 1
79 id ⊢ A = 1 ∧ B = 1 → A = 1 ∧ B = 1
80 79 ex ⊢ A = 1 → B = 1 → A = 1 ∧ B = 1
81 78 80 syl6 ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → A 2 = 1 → B = 1 → A = 1 ∧ B = 1
82 75 81 sylbid ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → 2 − 1 = A 2 → B = 1 → A = 1 ∧ B = 1
83 82 com23 ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → B = 1 → 2 − 1 = A 2 → A = 1 ∧ B = 1
84 70 83 syld ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → B 2 = 1 → 2 − 1 = A 2 → A = 1 ∧ B = 1
85 84 imp ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ B 2 = 1 → 2 − 1 = A 2 → A = 1 ∧ B = 1
86 67 85 sylbid ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ B 2 = 1 → A 2 + B 2 = 2 → A = 1 ∧ B = 1
87 86 impancom ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ A 2 + B 2 = 2 → B 2 = 1 → A = 1 ∧ B = 1
88 nn0re ⊢ B ∈ ℕ 0 → B ∈ ℝ
89 nn0ge0 ⊢ B ∈ ℕ 0 → 0 ≤ B
90 88 89 sqrtsqd ⊢ B ∈ ℕ 0 → B 2 = B
91 90 eqcomd ⊢ B ∈ ℕ 0 → B = B 2
92 91 eqeq1d ⊢ B ∈ ℕ 0 → B = 2 ↔ B 2 = 2
93 88 sqge0d ⊢ B ∈ ℕ 0 → 0 ≤ B 2
94 2re ⊢ 2 ∈ ℝ
95 94 a1i ⊢ B ∈ ℕ 0 → 2 ∈ ℝ
96 27 a1i ⊢ B ∈ ℕ 0 → 0 ≤ 2
97 sqrt11 ⊢ B 2 ∈ ℝ ∧ 0 ≤ B 2 ∧ 2 ∈ ℝ ∧ 0 ≤ 2 → B 2 = 2 ↔ B 2 = 2
98 3 93 95 96 97 syl22anc ⊢ B ∈ ℕ 0 → B 2 = 2 ↔ B 2 = 2
99 92 98 bitrd ⊢ B ∈ ℕ 0 → B = 2 ↔ B 2 = 2
100 id ⊢ 2 = B → 2 = B
101 100 eqcoms ⊢ B = 2 → 2 = B
102 101 eleq1d ⊢ B = 2 → 2 ∈ ℚ ↔ B ∈ ℚ
103 102 adantl ⊢ B ∈ ℕ 0 ∧ B = 2 → 2 ∈ ℚ ↔ B ∈ ℚ
104 103 notbid ⊢ B ∈ ℕ 0 ∧ B = 2 → ¬ 2 ∈ ℚ ↔ ¬ B ∈ ℚ
105 nn0z ⊢ B ∈ ℕ 0 → B ∈ ℤ
106 zq ⊢ B ∈ ℤ → B ∈ ℚ
107 105 106 syl ⊢ B ∈ ℕ 0 → B ∈ ℚ
108 107 pm2.24d ⊢ B ∈ ℕ 0 → ¬ B ∈ ℚ → A = 1 ∧ B = 1
109 108 adantr ⊢ B ∈ ℕ 0 ∧ B = 2 → ¬ B ∈ ℚ → A = 1 ∧ B = 1
110 104 109 sylbid ⊢ B ∈ ℕ 0 ∧ B = 2 → ¬ 2 ∈ ℚ → A = 1 ∧ B = 1
111 110 com12 ⊢ ¬ 2 ∈ ℚ → B ∈ ℕ 0 ∧ B = 2 → A = 1 ∧ B = 1
112 111 expd ⊢ ¬ 2 ∈ ℚ → B ∈ ℕ 0 → B = 2 → A = 1 ∧ B = 1
113 35 112 sylbi ⊢ 2 ∉ ℚ → B ∈ ℕ 0 → B = 2 → A = 1 ∧ B = 1
114 34 113 ax-mp ⊢ B ∈ ℕ 0 → B = 2 → A = 1 ∧ B = 1
115 99 114 sylbird ⊢ B ∈ ℕ 0 → B 2 = 2 → A = 1 ∧ B = 1
116 115 ad2antlr ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ A 2 + B 2 = 2 → B 2 = 2 → A = 1 ∧ B = 1
117 57 87 116 3jaod ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ A 2 + B 2 = 2 → B 2 = 0 ∨ B 2 = 1 ∨ B 2 = 2 → A = 1 ∧ B = 1
118 13 117 syld ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ A 2 + B 2 = 2 → B 2 ≤ 2 → A = 1 ∧ B = 1
119 9 118 sylbid ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ A 2 + B 2 = 2 → B 2 ≤ A 2 + B 2 → A = 1 ∧ B = 1
120 7 119 mpd ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ A 2 + B 2 = 2 → A = 1 ∧ B = 1
121 120 ex ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → A 2 + B 2 = 2 → A = 1 ∧ B = 1
122 oveq1 ⊢ A = 1 → A 2 = 1 2
123 sq1 ⊢ 1 2 = 1
124 122 123 eqtrdi ⊢ A = 1 → A 2 = 1
125 oveq1 ⊢ B = 1 → B 2 = 1 2
126 125 123 eqtrdi ⊢ B = 1 → B 2 = 1
127 124 126 oveqan12d ⊢ A = 1 ∧ B = 1 → A 2 + B 2 = 1 + 1
128 1p1e2 ⊢ 1 + 1 = 2
129 127 128 eqtrdi ⊢ A = 1 ∧ B = 1 → A 2 + B 2 = 2
130 121 129 impbid1 ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → A 2 + B 2 = 2 ↔ A = 1 ∧ B = 1