Metamath Proof Explorer


Theorem 2sqlem1

Description: Lemma for 2sq . (Contributed by Mario Carneiro, 19-Jun-2015)

Ref Expression
Hypothesis 2sq.1 S = ran w i w 2
Assertion 2sqlem1 A S x i A = x 2

Proof

Step Hyp Ref Expression
1 2sq.1 S = ran w i w 2
2 1 eleq2i A S A ran w i w 2
3 fveq2 w = x w = x
4 3 oveq1d w = x w 2 = x 2
5 4 cbvmptv w i w 2 = x i x 2
6 ovex x 2 V
7 5 6 elrnmpti A ran w i w 2 x i A = x 2
8 2 7 bitri A S x i A = x 2