Metamath Proof Explorer


Theorem 3sstr3g

Description: Substitution of equality into both sides of a subclass relationship. (Contributed by NM, 1-Oct-2000)

Ref Expression
Hypotheses 3sstr3g.1 φ A B
3sstr3g.2 A = C
3sstr3g.3 B = D
Assertion 3sstr3g φ C D

Proof

Step Hyp Ref Expression
1 3sstr3g.1 φ A B
2 3sstr3g.2 A = C
3 3sstr3g.3 B = D
4 2 3 sseq12i A B C D
5 1 4 sylib φ C D