Metamath Proof Explorer


Theorem 3wlkdlem1

Description: Lemma 1 for 3wlkd . (Contributed by AV, 7-Feb-2021)

Ref Expression
Hypotheses 3wlkd.p ⊢ P = ⟨“ ABCD ”⟩
3wlkd.f ⊢ F = ⟨“ JKL ”⟩
Assertion 3wlkdlem1 ⊢ P = F + 1

Proof

Step Hyp Ref Expression
1 3wlkd.p ⊢ P = ⟨“ ABCD ”⟩
2 3wlkd.f ⊢ F = ⟨“ JKL ”⟩
3 1 fveq2i ⊢ P = ⟨“ ABCD ”⟩
4 s4len ⊢ ⟨“ ABCD ”⟩ = 4
5 df-4 ⊢ 4 = 3 + 1
6 4 5 eqtri ⊢ ⟨“ ABCD ”⟩ = 3 + 1
7 2 fveq2i ⊢ F = ⟨“ JKL ”⟩
8 s3len ⊢ ⟨“ JKL ”⟩ = 3
9 7 8 eqtr2i ⊢ 3 = F
10 9 oveq1i ⊢ 3 + 1 = F + 1
11 6 10 eqtri ⊢ ⟨“ ABCD ”⟩ = F + 1
12 3 11 eqtri ⊢ P = F + 1