Metamath Proof Explorer


Theorem 3wlkdlem8

Description: Lemma 8 for 3wlkd . (Contributed by Alexander van der Vekens, 12-Nov-2017) (Revised by AV, 7-Feb-2021)

Ref Expression
Hypotheses 3wlkd.p ⊢ P = ⟨“ ABCD ”⟩
3wlkd.f ⊢ F = ⟨“ JKL ”⟩
3wlkd.s ⊢ φ → A ∈ V ∧ B ∈ V ∧ C ∈ V ∧ D ∈ V
3wlkd.n ⊢ φ → A ≠ B ∧ A ≠ C ∧ B ≠ C ∧ B ≠ D ∧ C ≠ D
3wlkd.e ⊢ φ → A B ⊆ I ⁡ J ∧ B C ⊆ I ⁡ K ∧ C D ⊆ I ⁡ L
Assertion 3wlkdlem8 ⊢ φ → F ⁡ 0 = J ∧ F ⁡ 1 = K ∧ F ⁡ 2 = L

Proof

Step Hyp Ref Expression
1 3wlkd.p ⊢ P = ⟨“ ABCD ”⟩
2 3wlkd.f ⊢ F = ⟨“ JKL ”⟩
3 3wlkd.s ⊢ φ → A ∈ V ∧ B ∈ V ∧ C ∈ V ∧ D ∈ V
4 3wlkd.n ⊢ φ → A ≠ B ∧ A ≠ C ∧ B ≠ C ∧ B ≠ D ∧ C ≠ D
5 3wlkd.e ⊢ φ → A B ⊆ I ⁡ J ∧ B C ⊆ I ⁡ K ∧ C D ⊆ I ⁡ L
6 1 2 3 4 5 3wlkdlem7 ⊢ φ → J ∈ V ∧ K ∈ V ∧ L ∈ V
7 s3fv0 ⊢ J ∈ V → ⟨“ JKL ”⟩ ⁡ 0 = J
8 s3fv1 ⊢ K ∈ V → ⟨“ JKL ”⟩ ⁡ 1 = K
9 s3fv2 ⊢ L ∈ V → ⟨“ JKL ”⟩ ⁡ 2 = L
10 7 8 9 3anim123i ⊢ J ∈ V ∧ K ∈ V ∧ L ∈ V → ⟨“ JKL ”⟩ ⁡ 0 = J ∧ ⟨“ JKL ”⟩ ⁡ 1 = K ∧ ⟨“ JKL ”⟩ ⁡ 2 = L
11 6 10 syl ⊢ φ → ⟨“ JKL ”⟩ ⁡ 0 = J ∧ ⟨“ JKL ”⟩ ⁡ 1 = K ∧ ⟨“ JKL ”⟩ ⁡ 2 = L
12 2 fveq1i ⊢ F ⁡ 0 = ⟨“ JKL ”⟩ ⁡ 0
13 12 eqeq1i ⊢ F ⁡ 0 = J ↔ ⟨“ JKL ”⟩ ⁡ 0 = J
14 2 fveq1i ⊢ F ⁡ 1 = ⟨“ JKL ”⟩ ⁡ 1
15 14 eqeq1i ⊢ F ⁡ 1 = K ↔ ⟨“ JKL ”⟩ ⁡ 1 = K
16 2 fveq1i ⊢ F ⁡ 2 = ⟨“ JKL ”⟩ ⁡ 2
17 16 eqeq1i ⊢ F ⁡ 2 = L ↔ ⟨“ JKL ”⟩ ⁡ 2 = L
18 13 15 17 3anbi123i ⊢ F ⁡ 0 = J ∧ F ⁡ 1 = K ∧ F ⁡ 2 = L ↔ ⟨“ JKL ”⟩ ⁡ 0 = J ∧ ⟨“ JKL ”⟩ ⁡ 1 = K ∧ ⟨“ JKL ”⟩ ⁡ 2 = L
19 11 18 sylibr ⊢ φ → F ⁡ 0 = J ∧ F ⁡ 1 = K ∧ F ⁡ 2 = L