Metamath Proof Explorer


Theorem 4cycl2v2nb

Description: In a (maybe degenerate) 4-cycle, two vertice have two (maybe not different) common neighbors. (Contributed by Alexander van der Vekens, 19-Nov-2017) (Revised by AV, 2-Apr-2021)

Ref Expression
Assertion 4cycl2v2nb ⊢ A B ∈ E ∧ B C ∈ E ∧ C D ∈ E ∧ D A ∈ E → A B B C ⊆ E ∧ A D D C ⊆ E

Proof

Step Hyp Ref Expression
1 prssi ⊢ A B ∈ E ∧ B C ∈ E → A B B C ⊆ E
2 prcom ⊢ D A = A D
3 2 eleq1i ⊢ D A ∈ E ↔ A D ∈ E
4 3 biimpi ⊢ D A ∈ E → A D ∈ E
5 prcom ⊢ C D = D C
6 5 eleq1i ⊢ C D ∈ E ↔ D C ∈ E
7 6 biimpi ⊢ C D ∈ E → D C ∈ E
8 prssi ⊢ A D ∈ E ∧ D C ∈ E → A D D C ⊆ E
9 4 7 8 syl2anr ⊢ C D ∈ E ∧ D A ∈ E → A D D C ⊆ E
10 1 9 anim12i ⊢ A B ∈ E ∧ B C ∈ E ∧ C D ∈ E ∧ D A ∈ E → A B B C ⊆ E ∧ A D D C ⊆ E