Metamath Proof Explorer


Theorem 4on

Description: Ordinal 3 is an ordinal number. (Contributed by Mario Carneiro, 5-Jan-2016)

Ref Expression
Assertion 4on 4 𝑜 On

Proof

Step Hyp Ref Expression
1 df-4o 4 𝑜 = suc 3 𝑜
2 3on 3 𝑜 On
3 2 onsuci suc 3 𝑜 On
4 1 3 eqeltri 4 𝑜 On