Metamath Proof Explorer


Theorem 4onn

Description: The ordinal 4 is a natural number. (Contributed by Mario Carneiro, 5-Jan-2016)

Ref Expression
Assertion 4onn ⊢ 4 𝑜 ∈ ω

Proof

Step Hyp Ref Expression
1 df-4o ⊢ 4 𝑜 = suc ⁡ 3 𝑜
2 3onn ⊢ 3 𝑜 ∈ ω
3 peano2 ⊢ 3 𝑜 ∈ ω → suc ⁡ 3 𝑜 ∈ ω
4 2 3 ax-mp ⊢ suc ⁡ 3 𝑜 ∈ ω
5 1 4 eqeltri ⊢ 4 𝑜 ∈ ω