Metamath Proof Explorer


Theorem 5p2e7

Description: 5 + 2 = 7. (Contributed by NM, 11-May-2004)

Ref Expression
Assertion 5p2e7 5+2=7

Proof

Step Hyp Ref Expression
1 df-2 2=1+1
2 1 oveq2i 5+2=5+1+1
3 5cn 5
4 ax-1cn 1
5 3 4 4 addassi 5+1+1=5+1+1
6 2 5 eqtr4i 5+2=5+1+1
7 df-6 6=5+1
8 7 oveq1i 6+1=5+1+1
9 6 8 eqtr4i 5+2=6+1
10 df-7 7=6+1
11 9 10 eqtr4i 5+2=7