Metamath Proof Explorer


Theorem 6p3e9

Description: 6 + 3 = 9. (Contributed by NM, 11-May-2004)

Ref Expression
Assertion 6p3e9 6 + 3 = 9

Proof

Step Hyp Ref Expression
1 df-3 3 = 2 + 1
2 1 oveq2i 6 + 3 = 6 + 2 + 1
3 6cn 6
4 2cn 2
5 ax-1cn 1
6 3 4 5 addassi 6 + 2 + 1 = 6 + 2 + 1
7 2 6 eqtr4i 6 + 3 = 6 + 2 + 1
8 df-9 9 = 8 + 1
9 6p2e8 6 + 2 = 8
10 9 oveq1i 6 + 2 + 1 = 8 + 1
11 8 10 eqtr4i 9 = 6 + 2 + 1
12 7 11 eqtr4i 6 + 3 = 9